Three numbers are in the ratio 3:4:5. If the sum of their cubes is 216000, find the largest of these three numbers.
1 answer:
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Answer:
i) 28 - 30i
ii) 36 + 28i
Step-by-step explanation:
i) x = 6 + i ⇒2x = 2(6 + i) = 12 + 2i
z = 4 - 8i ⇒ 4z = 4(4 - 8i) = 16 - 32i
2x + 4z = (12 + 2i) + (16 - 32i) = 28 - 30i
ii) w = -1 + 5i and z = 4 - 8i
w × z = (-1 + 5i)(4 - 8i) = -4 + 8i + 20i - 40⇒collect like terms
w × z = -4 + 28i - 40
∵
∴w × z = -4 + 28i - 40(-1) = -4 + 28i + 40 = 36 + 28i