Three numbers are in the ratio 3:4:5. If the sum of their cubes is 216000, find the largest of these three numbers.
1 answer:
Answer:
50
Step-by-step explanation:
Let the numbers be 3x, 4x, 5x
(3x)^3 + (4x)^3 + (5x)^3 = 216000
27x^3 + 64x^3 + 125x^3 = 216000
216x^3 = 216000
x^3 = 1000
x = 10
5x = 5(10) = 50
Answer: 50
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This might be wrong but probably y= 0.5x ?
The answer you want would be -120
b/c 200/5 is 40 so -3*40 is <em>-120</em>
Answer:
7
Step-by-step explanation:
