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aleksklad [387]
3 years ago
11

The credit remaining on a phone card (in dollars) is a linear function of the total calling time made with the card (in minutes)

. The remaining credit after minutes of calls is , and the remaining credit after minutes of calls is . What is the remaining credit after minutes of calls?
Mathematics
1 answer:
mr Goodwill [35]3 years ago
8 0

Answer and Step-by-step explanation: Suppose remaining credit is y and time in minutes is x. To determine a value of y corresponding to a value of x, first find the equation for the function.

Since the function is linear, the equation is of the form: y = mx + b. To determine it:

1) Find slope, or inclination, of the line:

slope (m) = \frac{y_{b}-y_{a}}{x_{b}-x_{a}}

where x's and y's are points of the function.

2) Determine the y-intercept, or b: Use a point of the function, replace them at the equation, y = mx + b, and find b.

3) The equation will be: y = mx + b

With the equation, replace x for the minutes the question is asking and calculate to find the remaining credit.

Th result will be a pair (x,y)

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The domain is the set of first numbers of the ordered pairs: {-1, 0, 1, 2}
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3 years ago
According to an article in Newsweek, the rate of water pollution in China is more than twice that measured in the US and more th
jeyben [28]

Answer:

(a) 0.119

(b) 0.1699

Solution:

As per the question:

Mean of the emission, \mu = 11.7 million ponds/day

Standard deviation, \sigma = 2.8 million ponds/day

Now,

(a) The probability for the water pollution to be at least 15 million pounds/day:

P(X\geq 15) = P(\frac{X - /mu}{\sigma} \geq \frac{15 - 11.7}{2.8})

P(X\geq 15) = P(Z \geq 1.178)

P(X\geq 15) = 1 - P(Z < 1.178)

Using the Z score table:

P(X\geq 15) = 1 - 0.881 = 0.119

The required probability is 0.119

(b) The probability when the water pollution is in between 6.2 and 9.3 million pounds/day:

P(6.2 < X < 9.3) = P(\frac{6.2 - 11.7}{2.8} < \frac{X - \mu}{\sigma} < \frac{9.3 - 11.7}{2.8})

P(6.2 < X < 9.3) = P(- 1.96 < Z < - 0.86)

P(6.2 < X < 9.3) = P(- 1.96 < Z < - 0.86)

P(Z < - 0.86) - P(Z < - 1.96)

Now, using teh Z score table:

0.1949 - 0.025 = 0.1699

4 0
3 years ago
If the mean of 5 positive integers is 15, what is the maximum possible difference between the largest and the smallest of these
Vikki [24]

Answer:

if the 5 numbers are different, the maximum difference is 64

Step-by-step explanation:

We have 5 positive (different) integers, a, b, c, d and e (suppose that are ordered from least to largest, so a is the smallest and b is the largest.

The mean will be:

M = (a + b + c + d + e)/5 = 15.

Now, if we want to find the largest difference between a and e, then we must first select the first 4 numbers as the smallest numbers possible, this is:

a = 1, b = 2, c = 3 and d = 4

M = (1 + 2 + 3 + 4 + d)/5 = 15

M = (10 + d)/5 = 15

10 + d = 15*5 = 75

d = 75 - 10 = 65

then the difference between a and d is = 65 - 1 = 64.

Now, if we take any of the first 4 numbers a little bit bigger, then we will see that the value of d must be smaller, and the difference between d and a will be smaller.

5 0
3 years ago
the midpoint of a horizontal line segment is at x=1 if the length of the line segment is 10.5. what absolute value equation coul
egoroff_w [7]

Answer: -4.25 ≤ x ≤ 6.25

Step-by-step explanation:

The midpoint of a segment is located at the same distance of each of the endpoints of the segment.

The midpoint is at x = 1.

The length of the segment is 10.5, if we divide it by two we have:

10.5/2 = 5.25

Now, if we want the endpoints to be at the same distance of the midpoint, then the endpoints will be:

Xmax = midpoint + 5.25

Xmin = midpoint - 5.25

Then the extremes are:

Xmax = 1 + 5.25 = 6.25

Xmin = 1 - 5.25 = -4.25

Then this segment can be written as:

Xmin ≤ x ≤ Xmax

-4.25 ≤ x ≤ 6.25

8 0
3 years ago
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Dahasolnce [82]

Answer:

6/11, 15/21, 9, 27/37, 31/54

Step-by-step explanation:

Absolute value is when you determine the distance between a value and zero . Since you will always have a positive distance, your absolute values are positive as well.

4 0
3 years ago
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