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aleksley [76]
3 years ago
10

I used to work at a jewelry store when I was a teenager. I sold watches that cost the company $20 for $150. What was the mark up

? Please hurry!!​
Mathematics
1 answer:
postnew [5]3 years ago
8 0

Answer:

$7.50

Step-by-step explanation:

$150 divided by 20 equals to 7.5 which equals to $7.50 as your mark up.

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James and Cameron are watching a film. They pause it with one fifth left to watch. What is the ratio of how much they have watch
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Answer:

The ratio of how much they have watched to how much they have left to see is 4 : 1.

Step-by-step explanation:

Consider that the total duration of the film is, 1.

It is provided that James and Cameron paused when there is one-fifth left to watch.

That is, they have already watched, 1-\frac{1}{5}=\frac{4}{5} th of the film.

Compute the ratio of how much they have watched to how much they have left to see as follows:

\frac{\text{Duration Watched}}{\text{Duration Left}}=\frac{4/5}{1/5}=\frac{4}{1}=4:1

Thus, the ratio of how much they have watched to how much they have left to see is 4 : 1.

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The wave rly brush company issued 4,000 shares of common stock worth 200,000.00 total. What is the par value of each share
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Solve: 2cos(x)-square root 3=0 for 0 less than x less than 2 pi
Leona [35]

Answer:

The general solution of   cos x = cos(\frac{\pi }{6})   is  

                                                x = 2nπ±\frac{\pi }{6}

The general solution values  

                                 x = - \frac{\pi }{6}  and x = \frac{\pi }{6}

Step-by-step explanation:

Explanation:-

Given equation is  

                              2cosx-\sqrt{3} =0  for 0

                              2cosx =\sqrt{3}

Dividing '2' on both sides, we get

                             cos x =\frac{\sqrt{3} }{2}

                             cos x = cos(\frac{\pi }{6})

<em>General solution of cos θ = cos ∝ is θ = 2nπ±∝</em>

<em>Now The general solution of   </em>cos x = cos(\frac{\pi }{6})<em>   is  </em>

<em>                                                 x = 2nπ±</em>\frac{\pi }{6}<em></em>

put n=0

x = - \frac{\pi }{6}  and x = \frac{\pi }{6}

Put n=1  

x = 2\pi +\frac{\pi }{6} = \frac{13\pi }{6}

x = 2\pi -\frac{\pi }{6} = \frac{11\pi }{6}

put n=2

x = 4\pi +\frac{\pi }{6} = \frac{25\pi }{6}

x = 4\pi -\frac{\pi }{6} = \frac{23\pi }{6}

And so on

But given 0 < x< 2π

The general solution values  

                                 x = - \frac{\pi }{6}  and x = \frac{\pi }{6}

                               

6 0
3 years ago
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