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ycow [4]
3 years ago
15

What is the answer pls tell​

Mathematics
1 answer:
mihalych1998 [28]3 years ago
8 0

Answer: Maddie is nine

Step-by-step explanation:

PETER: 9

Kelly: 12

MAX: 14

Ashley: 11

Maddie: 9

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In an arithmetic sequence, the seventh term is −9 and the nineteenth term is 39.
Stella [2.4K]

Answer:

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Step-by-step explanation:

3 0
3 years ago
Find the solution set of this inequality|10x+20| ≤10
Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

|10x+20|\leq 10

Firstly, we will find critical values

so, let's assume it is equal

|10x+20|= 10

now, we can break absolute sign

For |10x+20|= -(10x+20):

-(10x+20)= 10

we can solve for x

-10x-20= 10

Add both sides by 20

-10x-20+20= 10+20

-10x= 30

Divide both sides by -10

and we get

x=-3

For |10x+20|= (10x+20):

(10x+20)= 10

we can solve for x

10x+20= 10

Subtract both sides by 20

10x+20-20= 10-20

10x= -10

Divide both sides by 10

and we get

x=-1

so, critical values are

x=-3

x=-1

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For (-\infty,-3):

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

|10\times -5+20|\leq 10

|-50+20|\leq 10

30\leq 10

so, this is FALSE

For [-3,-1]:

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

|10\times -2+20|\leq 10

|-20+20|\leq 10

0\leq 10

so, this is TRUE

For (-1,\infty):

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

|10\times 0+20|\leq 10

|0+20|\leq 10

20\leq 10

so, this is FALSE

so, solution is

[-3,-1]

7 0
3 years ago
What does 1 - 0.0098 equal?
elena-s [515]
The answer is 0.9902 please give 5 stars if helpful
5 0
3 years ago
What are the vertical asymptotes of f(x) = 10/ x^2 - 1
Veronika [31]

Vertical asymptotes ares found where the function is undefined.  f(x) is undefined when the denominator equals zero:

x^2-1=0

<em>*Add 1 to both sides*</em>

x^2=1

<em>*Take the square root of both sides*</em>

x=+/-1

There are vertical asymptotes at x=-1 and x=1.

Hope this helps!!

8 0
3 years ago
Identify the sampling technique used for the following study.
ivanzaharov [21]

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