The perimeter of a rectangular field is 340 yd. The length is 30 yd longer than the width. Find the dimensions.
1 answer:
Let x = width x + 30 = length 2x + 2(x+30) = 340 4x + 60 = 340 4x = 280 x = 70 Width x = 70 yd
Length x + 30= 100 yd
Perimeter = 2l + 2w= 2l=200 w=140 200+140 = 340 yd
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