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Vlada [557]
2 years ago
6

The volume, V, of a certain cone can be found using the formula V= 1/3 B (25). where

Mathematics
2 answers:
juin [17]2 years ago
8 0
V=1/3 B(25)
V= 1/3 (90x25)
V=1/3 x 2250
V=2250/3
V=750 cubic meters
Olenka [21]2 years ago
5 0

Answer:

Wow! This is hard. I will try i answer it but for now other people will have ze chance

Step-by-step explanation:

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At the market, 5 light bulbs cost $9. How much do 7 light bulbs cost?
Rudiy27
Hello!

To solve this, find the cost of a single light bulb first, by dividing 9 / 5.

9 / 5 ==> 1.80

One light bulb is $1.80

Now, multiply 1.80 by 7.

1.80 * 7 = 12.6

7 light bulbs cost $12.6

Hope this helps! ☺♥


6 0
3 years ago
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Please help me. will mark brainliest. what is the answer?
VARVARA [1.3K]

Answer:

A ) y=-1/2x+2

Step-by-step explanation:

since the equation is y=2x+4 and the points are (-2,3) and the line is perpendicular to that equation

y=-1/2x+b

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3 years ago
Proving theorems about triangles
daser333 [38]

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Step-by-step explanation:

. should be a right angle triangle,

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7 0
2 years ago
Can somebody please solve this one question?
Volgvan

Answer:

1 ft

Step-by-step explanation:

Look at it this way, 200:4 is equivalent to 50:1 in which the number 1 is how wide the building is in the model.

6 0
2 years ago
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The sides of a triangle are x,x+1,2x-1 and its area is x root 10. Find the value of x
Marianna [84]
<span>You can use Heron's formula to solve this problem.

</span>A= \sqrt{s(s-a)(s-b)(s-c)} , where A is the area; a,b,с are the sides;  s<span> is the </span>semiperimeter<span> of the triangle
</span>s= \frac{a+b+c}{2}

<span>According to conditions:
</span>a = x
b = x+1
с = 2x-1

<span>Calculate the semiperimeter:
</span>s= \frac{x+x+1+2x-1}{2} = \frac{4x}{2}=2x

<span>Now we can compose and solve the equation according to Heron's formula:
</span>\sqrt{2x(2x-x)(2x-(x+1))(2x-(2x-1))}=x \sqrt{10}   \\  \sqrt{2x(x)(2x-x-1)(2x-2x+1)}=x \sqrt{10} \\  \sqrt{2x^2(x-1)(1)}=x \sqrt{10} \\  \sqrt{2x^3-2x^2}=x \sqrt{10}  \  \  \ |()^2 \\ 2x^3-2x^2=10x^2 \\ 2x^3-2x^2-10x^2=0 \\ 2x^3-12x^2=0 \ \ |:2 \\ x^3-6x^2=0 \\ x^2(x-6)=0 \\  \\ x^2=0 \\ x=0 \ \ \ \O \\ or \\ x-6=0 \\ x=6

<span>As a result, x = 6 is your answer.
 
I hope this helped.</span>
7 0
2 years ago
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