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Setler [38]
3 years ago
14

Angelo earns $2,080 each month. His total deductions are 30% of his pay. How much is deducted from his pay each month

Mathematics
2 answers:
vovangra [49]3 years ago
8 0
Each month, 2080 * 0.3 or $624 is deducted from Angelo's pay.
Olenka [21]3 years ago
7 0
624 is how much is deducted from his pay every month
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Which expression is equivalent to ( xy -6)2 for all values of x and y where the expression is defined?
hichkok12 [17]

Answer:

 ( x y -6)²  =  x² y² - 12 xy + 36            

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given that the expression ( x y -6)²

Apply formula (a-b)² = a² -2ab + b²

( x y -6)² = (xy)² - 2 × xy× 6 + (6)²

             = x² y² - 12 xy + 36

( x y -6)²  =  x² y² - 12 xy + 36            

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3 years ago
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Brut [27]
That doesn’t make any sense to me sorry
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Un número entero de tres dígitos es igual a 25 veces la suma de sus dígitos. Si los tres dígitos se invierten, el número que res
Pavlova-9 [17]
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5 0
4 years ago
I don’t understand this someone pls help me! (Question 10)
Likurg_2 [28]

Answer:

  a. f(n) = n(n+1)/2

  b. 351

  c. 19

  d. no; n would not be an integer for f(n) = 17.

Step-by-step explanation:

a. The terms are 1, 3, 6, 10, ...

Each term has the term number added to the previous term. That is, first differences are 3-1 = 2, 6-3 = 3, 10-6 = 4. These differences have a constant difference of 1.

When the 2nd differences are constant, a 2nd degree polynomial can describe the sequence. It is a little bit of trouble to find that polynomial.

For the polynomial ...

  f(n)=an^2+bn+c

We can substitute values for n and f(n) to get 3 equations in 3 unknowns:

  1=a\cdot1^2+b\cdot1+c\\\\3=a\cdot2^2+b\cdot2+c\\\\6=a\cdot3^2+b\cdot3+c

Solving these equations by your favorite method gives ...

  (a, b, c) = (1/2, 1/2, 0)

That is, the function representing the relationship is ...

  f(n) = n(n+1)/2 . . . . the function describing the relationship

__

b. f(26) = 26(27) = 13(27) = 351 . . . . the number of squares in term 26

__

c. The number of the term having 190 squares can be found by solving ...

  n(n +1)/2 = 190

  n(n +1) = 380 = 19(20)

The 19th term will have 190 squares.

__

d. Terms 5 and 6 are 15 and 21.

17 is not the value of one of the terms in this sequence.

6 0
3 years ago
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