X would be equal to -11 Im pretty darn sure
Step-by-step explanation:
The slope-intercept form is y=mx+b y = m x + b , where m m is the slope and b b is the y-intercept. Find the values of m m and b b using the form y=mx+b y = m x + b .
(x+y) / 2 =7
multiply both sides by 2
x+y=14
3x=.5y
divide both sides by .5
6x=y
plug 6x in for y
x+(6x)=14
simplify
7x=14
divide both sides by 7
x=2
![\bf y=r(x)=\sqrt[3]{x}\quad x= \begin{cases} -2.197\\ -1.331\\ 0\\ 1.331\\ 2.197\\ 3.375\\ 4.913 \end{cases}\implies y= \begin{cases} \sqrt[3]{-2.197}\\ \sqrt[3]{-1.331}\\ \sqrt[3]{0}\\ \sqrt[3]{1.331}\\ \sqrt[3]{2.197}\\ \sqrt[3]{3.375}\\ \sqrt[3]{4.913} \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20y%3Dr%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D%5Cquad%20x%3D%0A%5Cbegin%7Bcases%7D%0A-2.197%5C%5C%0A-1.331%5C%5C%0A0%5C%5C%0A1.331%5C%5C%0A2.197%5C%5C%0A3.375%5C%5C%0A4.913%0A%5Cend%7Bcases%7D%5Cimplies%20y%3D%0A%5Cbegin%7Bcases%7D%0A%5Csqrt%5B3%5D%7B-2.197%7D%5C%5C%0A%5Csqrt%5B3%5D%7B-1.331%7D%5C%5C%0A%5Csqrt%5B3%5D%7B0%7D%5C%5C%0A%5Csqrt%5B3%5D%7B1.331%7D%5C%5C%0A%5Csqrt%5B3%5D%7B2.197%7D%5C%5C%0A%5Csqrt%5B3%5D%7B3.375%7D%5C%5C%0A%5Csqrt%5B3%5D%7B4.913%7D%0A%5Cend%7Bcases%7D)
so.. .get the pair and plot them then, all you need is your calculator to get the cubic root of the provided value.
Answer:
The radius is: 1
Step-by-step explanation:
The equation of a circle in center-radius form is:

Where the center is at the point (h, k) and the radius is "r".
Given the equation of the circle:

You can identify that:

Then, solving for "r", you get that the radius of the circle is:
