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4 years ago

37.362 is 7 4/5 % of what number?

1 answer:

6 0

To find the answer you just need to multiply 37.362 by .7 4/5 and add that answer to 37.362 and you get 62.27.
Hope i help

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What is the difference quotient of the function g(x) = 4^x

lidiya [134]

Answer:

First choice

Step-by-step explanation:

The difference quotient in general is $\frac{g(x+h)-g(x)}{h}$ . To get an expression for $g(x+h)$ , replace x with x + h.

For this question,

$\frac{4^{x+h}-4^x}{h}=\frac{4^x\cdot4^h-4^x}{h}$

Factor $4^x$ out of the numerator.

$\frac{4^x(4^h-1)}{h}$

8 0

3 years ago

Peter is a beekeeper who sells jars of honey and combs at the market. For each 10 jars of honey that he takes to the market carr

dsp73

Can you list the options? so i can help, theres not enough info for me to answer

5 0

3 years ago

A particle is projected with a velocity of <img src="https://tex.z-dn.net/?f=40ms%5E-%5E1" id="TexFormula1" title="40ms^-^1" alt

Katena32 [7]

Answer:

$2\sqrt{55}\text{ m/s or }\approx 14.8\text{m/s}$

Step-by-step explanation:

The vertical component of the initial launch can be found using basic trigonometry. In any right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. Let the vertical component at launch be $y$ . The magnitude of $40\text{ m/s}$ will be the hypotenuse, and the relevant angle is the angle to the horizontal at launch. Since we're given that the angle of elevation is $60^{\circ}$ , we have:

$\sin 60^{\circ}=\frac{y}{40},\\y=40\sin 60^{\circ},\\y=20\sqrt{3}$ (Recall that $\sin 60^{\circ}=\frac{\sqrt{3}}{2}$ )

Now that we've found the vertical component of the velocity and launch, we can use kinematics equation $v_f^2=v_i^2+2a\Delta y$ to solve this problem, where $v_f/v_i$ is final and initial velocity, respectively, $a$ is acceleration, and $\Delta y$ is distance travelled. The only acceleration is acceleration due to gravity, which is approximately $9.8\:\mathrm{m/s^2}$ . However, since the projectile is moving up and gravity is pulling down, acceleration should be negative, represent the direction of the acceleration.

What we know:

$v_i=20\sqrt{3}\text{ m/s}$
$a=-9.8\:\mathrm{m/s^2}$
$\Delta y =50\text{ m}$

Solving for $v_f$ :

$v_f^2=(20\sqrt{3})^2+2(-9.8)(50),\\v_f^2=1200-980,\\v_f^2=220,\\v_f=\sqrt{220}=\boxed{2\sqrt{55}\text{ m/s}}$

3 0

3 years ago

Maya designed two intersecting roads. She drew the roads so that one of the angles at the intersection was 45 degrees. What are

Citrus2011 [14]

The sum of opposite angles are equal, so two of the angles are 45°. The sum of all angles about the intersection of two lines is 360°. So the remaining two angles are found by:

α=(360-2*45)/2

α=135° thus all four angles are:

45°,135°,45°,135°

4 0

3 years ago

Round the following percentages to one decimal place.0.698%53.123%0.075%34.337%3.876%

balandron [24]

To round off a given number in decimals to one decimal place (1 dp), we simply take the figure right after the decimal and approximate the remaining after it. If the second number after the decimal is a significant number (5 and above) we make it 1 and add to the number right after the decimal. If its NOT a significant number, we simply disregard it. The solutions therefore are;

ANSWER:

$\begin{gathered} \text{Rounded to one decimal place;} \\ (1)0.698\%\approx0.7 \\ (2)53.123\%\approx53.1 \\ (3)0.075\%\approx0.1 \end{gathered}$

Notice how the number in (1) becomes 0.7, after taking the next number (which is 9) and adding it as 1 to the number after the decimal (which is 6). The same applies to the number in (3).

$\begin{gathered} (4)34.337\%\approx34.3 \\ (5)3.876\%\approx3.9 \end{gathered}$

4 0

1 year ago