The number of advance tickets sold is 25 and same day tickets sold is 30.
Data Given;
- Advance Ticket = $30
- Same-day Ticket = $25
- Total Ticket = $60
- Total Cost of Ticket = $1625
<h3>System of Equations</h3>
Let the number of advance ticket be represented by x
Let the number of same-day ticket be represented by y
From the system of equations above, we can easily pick any to start our calculation.
Using equation (i),
x + y = 60
x = 60 - y ...equation(iii)
Put equation (iii) into equation (ii)
Put the value of y into equation (i)
From the calculation above, the number of advance tickets sold is 25 and same-day tickets is 30.
Learn more on system of equations here;
brainly.com/question/13729904
N-6/3=4
<span>n in (-oo:+oo)
n-(6/3) = 4 // - 4
n-(6/3)-4 = 0
n-4-2 = 0
n-6 = 0 // + 6
n = 6
n = 6
</span>
Hope this could help : )
You need to use pythagorean’s theorem. so a^2+b^2=c^2.
in this case it would be 6^2+8^2=c2
36+64=100
the square root of 100 is 10
x=10
Answer:
that is the solution to the question
Answer:
![\left[\begin{array}{ccc}-32\\4\\20\\-36\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-32%5C%5C4%5C%5C20%5C%5C-36%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
The product of a scalar times the matrix involves the product of that scalar times each of the elements of the matrix, resulting on the multiplication by "-4" of each of the four elements as shown below. These new product values end up being the new matrix elements.
![-4*\left[\begin{array}{ccc}8\\-1\\-5\\9\end{array}\right] = \left[\begin{array}{ccc}-32\\4\\20\\-36\end{array}\right]](https://tex.z-dn.net/?f=-4%2A%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D8%5C%5C-1%5C%5C-5%5C%5C9%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-32%5C%5C4%5C%5C20%5C%5C-36%5Cend%7Barray%7D%5Cright%5D)
