3 consecutive odd integers....x, x + 2, and x + 4
x + x + 4 = 3(x + 2) - 131
2x + 4 = 3x + 6 - 131
2x + 4 = 3x - 125
2x - 3x = - 125 - 4
-x = - 129
x = 129
x + 2 = 129 + 2 = 131
x + 4 = 129 + 4 = 133
so ur 3 odd numbers are : 129,131, and 133 <==
Answer:
You should probably be more specific as different schools have different curriculum's!
Step-by-step explanation:
The distance formula is shown here. If you plug your coordinates into the formula, you will get d=square root of (5-3)^2+(8-10)^2 which equals 2.828
<span>So you have composed two functions,
</span><span>h(x)=sin(x) and g(x)=arctan(x)</span>
<span>→f=h∘g</span><span>
meaning
</span><span>f(x)=h(g(x))</span>
<span>g:R→<span>[<span>−1;1</span>]</span></span>
<span>h:R→[−<span>π2</span>;<span>π2</span>]</span><span>
And since
</span><span>[−1;1]∈R→f is defined ∀x∈R</span><span>
And since arctan(x) is strictly increasing and continuous in [-1;1] ,
</span><span>h(g(]−∞;∞[))=h([−1;1])=[arctan(−1);arctan(1)]</span><span>
Meaning
</span><span>f:R→[arctan(−1);arctan(1)]=[−<span>π4</span>;<span>π4</span>]</span><span>
so there's your domain</span>
U se the midpoint formula to find the midpoint of the line segment.
(5/2,5) or (5,5/2) it’s one of them .gotta be I’m pretty sure it’s (5/2,5)
