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gayaneshka [121]
2 years ago
10

I need help on this

Mathematics
2 answers:
sveta [45]2 years ago
6 0

Answer:

c

Step-by-step explanation:

A relation between two sets is a collection of ordered pairs containing one object from each set. If the object x is from the first set and the object y is from the second set, then the objects are said to be related if the ordered pair (x,y) is in the relation.

A function is a relation from a set of inputs to a set of possible outputs where each input is related to exactly one output.

The graph represents the relation, but not a function.

This is relation, because it defines the rule for each  some  such, that the ordered pair (x,y) lies on the graph.

This is not a function, because for all input values of x (excluding x=3) we can find two different output values of  y.

oksian1 [2.3K]2 years ago
3 0

Answer:

c

Step-by-step explanation:

Hope this helps ya'll

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Shards of clay vessels were put together to reconstruct rim diameters of the original ceramic vessels found at the Wind Mountain
Otrada [13]

Answer:

a) In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)^2}{n-1}} (3)  

The mean calculated for this case is

The sample deviation calculated s=3.46 \approx 3.5

b) 15.8-1.383\frac{3.5}{\sqrt{10}}=14.27    

15.8+1.383\frac{3.5}{\sqrt{10}}=17.33    

So on this case the 80% confidence interval would be given by (14.27;17.33)  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Part a

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)^2}{n-1}} (3)  

The mean calculated for this case is

The sample deviation calculated s=3.46 \approx 3.5

Part b

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=10-1=9

Since the Confidence is 0.80 or 80%, the value of \alpha=0.2 and \alpha/2 =0.1, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.1,9)".And we see that t_{\alpha/2}=1.383

Now we have everything in order to replace into formula (1):

15.8-1.383\frac{3.5}{\sqrt{10}}=14.27    

15.8+1.383\frac{3.5}{\sqrt{10}}=17.33    

So on this case the 80% confidence interval would be given by (14.27;17.33)    

6 0
3 years ago
9x + 27 = –72 what is x
Brilliant_brown [7]
9x + 27  = -72
       - 27 = - 27
        9x  = - 99
      9x/9 = -99/9
          x  = -11
5 0
2 years ago
Find each angle measure to the nearest degree.<br> 15) tan C = 0.1405
Ivanshal [37]

Answer:

C=8^o

Step-by-step explanation:

To find the angle C given the equation tan(C)=0.1405, use the "arctan" function [which is the inverse function of tangent] on both sides of the equation as shown below:

tan(C)=0.1405\\arctan(tan(C)) = arctan(0.1405)\\C=arctan(0.1405)\\C=7.9977^o

This can be rounded to the nearest degree as: C=8^o

3 0
3 years ago
Solve for the variable <br><br><br> u^2 + 2 = 11
stira [4]

Answer:

There are two roots:  -3 and 3

Step-by-step explanation:

Combine the like terms first.  We get u^2 = 9.

There are two roots:  -3 and 3.

8 0
3 years ago
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zimovet [89]
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