What degree rotation mapped R(5,-6) to R’(6,5)?

Please help me. Please no guessing!!!! Thank you!!

prisoha [69]

I THINK ANSWER IS D, B HAS HIGHER MEAN THAN A

8 0

4 years ago

-18 > |-1 (3-2x)| > 18

12345 [234]

Answer:

No Solution

Step-by-step explanation:

Since -18 > 18 is not true, this inequality is always false

4 0

4 years ago

Read 2 more answers

Luke and Quinten are discussing what shapes the composite figure can be broken into. Luke wants to break it into four right tria

Lapatulllka [165]

Answer:

it's C

Step-by-step explanation:

i took the test and got it right

6 0

2 years ago

A school library has 200 DVDs in its collection. Given that 40% of the DVDs are about science and 45% are about history, how man

Paladinen [302]

Answer:

The last 15 percent of that would be 39

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

The marketing manager for an automobile manufacturer is interested in determining the proportion of new compact-car owners who w

Serhud [2]

Answer:

$z=\frac{0.395 -0.3}{\sqrt{\frac{0.3(1-0.3)}{200}}}=2.932$

$p_v =2*P(z>2.932)=0.0034$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of people that they would have purchased the GPS navigation system is significantly different from 0.3

Step-by-step explanation:

Data given and notation

n=200 represent the random sample taken

X=79 represent the number of people that they would have purchased the GPS navigation system

$\hat p=\frac{79}{200}=0.395$ estimated proportion of people that they would have purchased the GPS navigation system

$p_o=0.3$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is 0.3 or no.:

Null hypothesis: $p=0.3$

Alternative hypothesis: $p \neq 0.3$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.395 -0.3}{\sqrt{\frac{0.3(1-0.3)}{200}}}=2.932$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z>2.932)=0.0034$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of people that they would have purchased the GPS navigation system is significantly different from 0.3

4 0

3 years ago