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3 years ago

5

Given ABC with A(0, 0), B(2, 3), and C(4,0), prove ABC is isosceles

1 answer:

Likurg_2 [28]3 years ago

5 0

Step-by-step explanation:

1. if to calculate the length of AB; AC and BC, then:

$|AB|=\sqrt{(2-0)^2+(3-0)^2} =\sqrt{13}.$

$|AC|=\sqrt{(4-0)^2+(0-0)^2} =4.$

$|BC|=\sqrt{(2-4)^2+(0-3)^2}= \sqrt{13}.$

2. if to compare the calculated lengths, then:

AB=BC. It means the given triangle is isosceles.

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