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erik [133]
3 years ago
5

Given ABC with A(0, 0), B(2, 3), and C(4,0), prove ABC is isosceles

Mathematics
1 answer:
Likurg_2 [28]3 years ago
5 0

Step-by-step explanation:

1. if to calculate the length of AB; AC and BC, then:

|AB|=\sqrt{(2-0)^2+(3-0)^2} =\sqrt{13}.

|AC|=\sqrt{(4-0)^2+(0-0)^2} =4.

|BC|=\sqrt{(2-4)^2+(0-3)^2}= \sqrt{13}.

2. if to compare the calculated lengths, then:

AB=BC. It means the given triangle is isosceles.

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Translate the following phrase below into an algebraic expression:
nexus9112 [7]
D. N/88=16
quotient means divisions so the quotient of a number and 88 is n/88.
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Write the numbers in order from greatest to least.<br> -4, 2 1⁄5, -2 3⁄4, 1⁄10
Leviafan [203]

Answer:

2 1/5, 1/10, - 2 3/4, -4

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TiliK225 [7]

we know that

For a polynomial, if x=a is a zero of the function, then (x−a) is a factor of the function. The term multiplicity, refers to the number of times that its associated factor appears in the polynomial.

So

In this problem

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then

the factors are

(x-2)\\ (x-3)\\ (x-5)

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The answer is No

If a cubic polynomial function has three different zeroes

then

the multiplicity of each factor is one

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x=2\\ x=3\\ x=5

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Step-by-step explanation:

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