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3 years ago

Given ABC with A(0, 0), B(2, 3), and C(4,0), prove ABC is isosceles

Mathematics

1 answer:

Likurg_2 [28]3 years ago

5 0

Step-by-step explanation:

1. if to calculate the length of AB; AC and BC, then:

$|AB|=\sqrt{(2-0)^2+(3-0)^2} =\sqrt{13}.$

$|AC|=\sqrt{(4-0)^2+(0-0)^2} =4.$

$|BC|=\sqrt{(2-4)^2+(0-3)^2}= \sqrt{13}.$

2. if to compare the calculated lengths, then:

AB=BC. It means the given triangle is isosceles.

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4 years ago

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3 years ago

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Answer:

$z=\frac{24-40}{8}=-2$

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And for this case we want to find the percentage of lightbulb replacement requests numbering between 24 and 40.

From the empirical rule we know that we have 68% of the values within one deviation from the mean, 95% of the values within 2 deviations and 99.7% within 3 deviations.

We can find the number of deviations from themean for the limits with the z score formula we got:

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And replacing we got:

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3 years ago

Which choice is equivalent to the fraction below? (Hint: Rationalize the denominator and simplify.) I NEED HELP HELP PLEASE PLEA

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Answer:

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Step-by-step explanation:

--------------

sqrt(x) + sqrt(x+2)

Multiply top and bottom by sqrt(x) - sqrt(x+2)

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------------------------ * --------------------------

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FOIL the denominator

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Distribute the minus sign

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6 0

3 years ago