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3 years ago

Write the numbers in order from greatest to least. -4, 2 1⁄5, -2 3⁄4, 1⁄10

Mathematics

2 answers:

Greeley [361]3 years ago

8 0

-4,-2, 1/10, 1/5, 3/4, 2

Leviafan [203]3 years ago

6 0

Answer:

2 1/5, 1/10, - 2 3/4, -4

Step-by-step explanation:

If you're ever confused about whether a number is greater than another number, think about them on a number line. If the number is further to the left than another number, it is less (for example, 0 is further to the left than 2).

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Michele wanted to measure the height of her school’s flagpole. She placed a mirror on the ground 48 feet from the flagpole, then

yulyashka [42]

Height of the flagpole = x
distance from flagpole to the mirror = 48 ft
height of Michele = 5 ft
distance from Michele to the mirror = 12 ft

Now, set the proportion.

x/48 = 5/12
48 * x/48 = 5/12 * 48
x = 240/12
x = 20

So, the height of the flagpole is 20 ft.

HOPE THIS HELPS!!!!

5 0

3 years ago

Perform the operation. Enter your answer in scientific notation. 9 x 10^*8 - 5.3 x 10^*8 =

PilotLPTM [1.2K]

Answer:

3.7x10^8

Step-by-step explanation:

did it on calc

3 0

3 years ago

-3(×+2)=12 what is x equal to

velikii [3]

Answer:

x=-6

Step-by-step explanation:

Follow along:

1. Distribute the -3 to those within the parenthesis.

-3x-6=12

2. Move the whole numbers to one sides, isolate the variable.

-3x=18

3. Divide both sides by -3

x=-6

7 0

3 years ago

What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove

wolverine [178]

Answer:

The solutions are:

$b=0,\:b=4$

Step-by-step explanation:

Considering the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

Solving the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

$\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c$

$5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2$

$5b^3-10=6b^3-4b^2-10$

$\mathrm{Switch\:sides}$

$6b^3-4b^2-10=5b^3-10$

$6b^3-4b^2-10+10=5b^3-10+10$

$6b^3-4b^2=5b^3$

$\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}$

$6b^3-4b^2-5b^3=5b^3-5b^3$

$b^3-4b^2=0$

$Using\:the\:Zero\:Factor\:Principle:$ $if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$