Answer:
I think it might be data and range
Step-by-step explanation:
the answer is at the top
Solution is in the picture
The scale length is 9cm and the scale is 6cm/15ft which is 3cm/5ft, so we can say:
9cm(5ft/3cm)=15ft for the length
If you wanted the width too...
4cm(5ft/3cm)=20ft/3 (6'8", 6ft 8in)
Answer:
(2y - 5) (3y^2 - 4)
Step-by-step explanation:
Group and factor by using the Greatest Common Factor (GCF).
6y^3 - 15y^2 - 8y + 20
Simply multiply the terms inside the first pair of parenthesis, by the terms in the second pair of parenthesis.
2y x 3y^2 = 6y^3
2y x (-4) = 8y
-5 x 3y^2 = 15y^2
-5 x (-4) = 20
6y^3 - 8y -15y^2 + 20
Now, simply simplify the problem!
(2y - 5) (3y^2 - 4)
Answer:
68+m=185
m=117
Step-by-step explanation:
68 miles before lunch, plus m miles after lunch is a total of 185 miles. Assuming she reaches her destination. That creates the equation 68+m=185
Then, to figure out the miles she travels after lunch we solve for m:
do this by subtracting 68 from both sides. This leaves us with: m=117
