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LenaWriter [7]
3 years ago
10

What is the coefficient in the term 7x? A.0 B.1 C.7 D.x

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
6 0

Answer:

C. 7

Step-by-step explanation:

The coefficient is the number before the variable.

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harina [27]

Answer:

3*4. and 0.3*42.00 and 0.03*42

Step-by-step explanation:

4 0
3 years ago
20 POINTS!!!!
nevsk [136]

Answer:

Step 1: Remove parentheses by multiplying factors.

= (x * x) + (1 * x) + (2 * x) + (2 * 1)

Step 2: Combine like terms by adding coefficients.

(x * x) = x2

(1 * x) = 1x

(2* x) = 2x

Step 3: Combine the constants.

(2 * 1) = 2

Step 4: Therefore, Simplifying Algebraic Expression is solved as

= x2 + 3x + 2.

3 0
3 years ago
Read 2 more answers
The residents of a downtown neighborhood designed a​ triangular-shaped park as part of a city beautification program. The park i
ycow [4]
You have x , x+7, and 7x-7. When you add those up and equal it to 180 you can get your x. X equals 20
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8 0
3 years ago
Please help. Also please show your work. Y/5 - 2/5
Maurinko [17]

Answer:

0.2(y-2)

Step-by-step explanation:

factor out 1/5 from the expression

1/5×(y-2)

0.2(y-2)

8 0
3 years ago
If a cannonball is shot directly upward with a velocity of 160 ft per​ second, its height above the ground after t seconds is gi
Contact [7]

Step-by-step explanation:

If a cannonball is shot directly upward with a velocity of 160 ft per​ second. Its height as a function of time is given by :

h(t)=160t-16t^2 .......(1)

t is in seconds

(a) Velocity is given by :

v=\dfrac{dh}{dt}\\\\v=\dfrac{d(160t-16t^2)}{dt}\\\\v=(160-32t)\ ft/s  

Acceleration is given by :

a=\dfrac{dv}{dt}\\\\a=\dfrac{d(160-32t)}{dt}\\\\a=-32\ ft/s^2

(b) For maximum height put \dfrac{dh}{dt}=0

i.e.

160-32t=0\\\\t=5\ s

Put t = 5 s in equation (1). So,

h(5)=160t-16t^2\\\\h(5)=160(5)-16(5)^2\\\\h(5)=400\ ft

(c) When the ball reaches ground, its height is equal to 0. So,

h(t) = 0

160t-16t^2=0\\\\t(160-16t)=0\\\\t=0,t=10\ s

Hence, this is the required solution.

4 0
3 years ago
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