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3 years ago

Substitute 3 for x and evaluate the expression below.

Mathematics

1 answer:

lana66690 [7]3 years ago

6 0

Answer:4

Step-by-step explanation:3-8=-5. But because it is in absolute value, it would be positive 5. And then 5-1=4.

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A rectangular swimming

netineya [11]

Answer:

Step-by-step explanation:

perimeter=150

lets name the length x

length=x

width=x-2

2[x±x-2]=150

2x±2x-4=150

4x=154

154÷4=77

x=77

5 0

3 years ago

Can someone help me with my homework it was due last week

marissa [1.9K]

Answer: For number 1, I think that -9.25 is not an integer. Number 2 it is -2. #3, the answer is $6.02. #4 is $15.31. #5 is B. 3/4 =15/6.

Step-by-step explanation:

I don't really know how to explain #1 to you, so sorry. Number 2 it is -2 because -5 + 13 is 8. Then when you subtract 10 from 8 you get -2. Number 3, the answer is $6.02 because you know that it costs $4.30 for each pound. She got 1.4 pounds of bacon. Multiply to find your answer. Number 4 is $15.31. Since you need to multiply 12.95 by 2. He got 2 shirts for 12.95 so that's why. Then add 8.79 to 12.95 to get $15.31. Number 5, 3/4 is not equivalent to 15/16. Hope this helps!!!!!

4 0

3 years ago

3 + x = 18 please help!!!!!!!!!!

Ierofanga [76]

Answer:

X=15

all you have to do is subtract 3 from 18 to get x

6 0

3 years ago

Read 2 more answers

HELP

kaheart [24]

Answer:

We find the perimeter using the distance formula between two points.

1) A(2, -4), B(-2, -1), C(-5, -5), D(-1, -8)

AB = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

= $\sqrt{(-2-2)^{2}+(-1+4)^{2} }$

= $\sqrt{25}$

= 5 units

Similarly, BC = 5 units

CD = 5 units

AD = 5 units

Perimeter = AB+BC+CD+AD = 20 units (E)

2) X(-2, 1), Y(4, 3), Z(5, -1)

XY = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

= $\sqrt{(4+2)^{2}+(3-1)^{2} }$

= √40 = 6.3

Similarly, YZ = √17 = 4.1

XZ = 7.3

Perimeter = XY+YZ+XZ = 17.7 units (C)

3) A(0, 4), B(4, 1), C(4, -4), D(-4, -4), E(-4, 1)

AB = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

= $\sqrt{(4-0)^{2}+(1-4)^{2} }$

= √25 = 5 units

BC = 5 units

CD = 8 units

DE = 5 units

AE = 5 UNITS

Perimeter = 28 units (B)

4) . T(-5, 0), U(7, 3), V(9, -6), W(-3, -9)

TU = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

= $\sqrt{(7+5)^{2}+(3-0)^{2} }$

= √153 = 12.4 units

UV = 9.2 units

VW = 12.4 units

TW = 9.2 units

Perimeter = 43.2 units (D)

5) S(-1, 6), T(-1, -8), U(7, -8)

ST = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

= $\sqrt{(-1+1)^{2}+(-8-6)^{2}}$

= 14 units

TU = 8 units

SU = 16.1 units

Perimeter = 38.1 units (A)

6) A(-7, 0), B(-3, 5), C(2, 1), D(-2, -4)

AB = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

= $\sqrt{(-3+7)^{2}+(5-0)^{2}}$

= 6.4 units units

BC = 6.4 units

CD = 6.4 units

AD = 6.4 units

Perimeter = 25.6 units (F)

6 0

3 years ago

PLZ HELP!!! Which graph represents the function?

SCORPION-xisa [38]

All three of those graphs are functions.

The main thing about a function is for every input in the domain there is exactly one output. That doesn't mean that there has to be a y for every x; the xs with no output, no y, are not in the domain of the function.

So to be a function for every x there needs to be at most one y.

The test for that is called the vertical line test. If you can draw a vertical line (x=constant) through two points of the graph, that graph does not represent a function.

All three of these functions pass the vertical line test. For the first the questionable point is x=-2. A vertical line there passes through the graph at y=0. It doesn't pass through the graph at y=-2 -- the open circle means that interval is open, it doesn't include (-2,-2). So a vertical line passes through at most one point on the graph at all (shown) places, therefore it's a function.

The second one is similar at x=-2. At x=0 there's an open point; the function has no value there. x=0 is not part of the domain. That doesn't mean this isn't a function; it passes the vertical line test, so it's a function.

The third is like the second except now at x=-2 the value's in the right branch, y=-8. Still this passes the vertical line test, so it's a function too.

Answer: all of the above

6 0

3 years ago