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pickupchik [31]
2 years ago
8

(8,9); x+3y=2 in y=mx+b form

Mathematics
1 answer:
n200080 [17]2 years ago
7 0

Answer:

use photo math. it will help

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In class A, John got 85 for his first test John's class mean was 75 and standard deviation was 5. In class B, Kathy got 80 in he
ivanzaharov [21]

Answer:

b. Kathy

Step-by-step explanation:

We compare each of their score by how far away from the mean when in term of the standard deviation. Using the following formula

\frac{x - \mu}{\sigma}

For John he is (85 - 75)/5 = 2.

For Kathy she is (80 - 50)/10 = 3.

Since Kathy is 3 standard deviation better than her class' average, while John is only 2's. We conclude that Kathy did better.

6 0
2 years ago
PLEASE HEWP EASY SCIENCE BRIANLIST U CAN BE IF CORRECT
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Step-by-step explanation:

4 0
3 years ago
CAN SOMEONE PLEASE HELP ME???
Varvara68 [4.7K]

Answer:

m=2

Step-by-step explanation:

slope is the average rate of change in a specific interval

we can calculate slope in this case with Δy/Δx or (y2-y1)/(x2-x1)

m=(y2-y1)/(x2-x1)

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5 0
2 years ago
Which of the following are solutions to the equation below?
Natasha2012 [34]
Both A and C would be solutions to the equation.

In order to solve for this you must first get the equation equal to 0. 

2x^2+5x+8=6 ----> subtract 6 from both sides
2x^2 + 5x + 2 = 0

Now knowing this we can use the coefficients of each one in descending order of power as a, b and c. 

a = 2 (because it is the coefficient to x^2)
b = 5 (because it is the coefficient to x)
c = 2 (because it is the end number)

Now we can plug these values into the quadratic equation. 

\frac{-b +/- \sqrt{b^{2} - 4ac } }{2a}

\frac{-5 +/- \sqrt{5^{2} - 4(2)(2) } }{2(2)}

\frac{-5 +/- \sqrt{9} }{4}

\frac{-5 +/- 3 }{4}

\frac{-5 + 3 }{4} or -1/2 for the first answer

\frac{-5 - 3 }{4} or -2 for the second answer

5 0
3 years ago
HELPPP ACELLUS ALGEBRA 2<br> Divide.<br> 3x^3 + 2x^2 – 3x + 54<br> /x + 3
il63 [147K]

Answer:

The answer is 5

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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