14 1/4
you just multiply the two
88.18 Lbs or pounds that just a short word for pounds hope this helps
C = child tickets
a = adult tickets
Solve this with the substitution method.
Make two equations:
6.30c + 9.90a = 1,246.50
c + a = 159
Solve for c.
Subtract 9.90a from both sides.
6.30c = 1,246.50 - 9.90a
Divide both sides by 6.30.
c = 197.86 - <span>1.57a (rounded to hundredths)
Plug c into second equation.
</span>197.86 - 1.57a + a = 159
Combine like terms.
197.86 - 0.57a = 159
Subtract 197.86 from both sides.
-0.57a = -38.86
Divide both sides by -0.57.
a = <span>68.18
round up to ones: 68
</span>
were sold.<span>
</span>
Answer:
A. Miguel has the greatest spread.
The range of the two persons can be determined by:
Adam's range = 106 -91
= 15
Miguel's range = 105 -86
= 19
B. Considering the middle 50% of the training time, the person with the least spread is Adam.
Adam - 103 105 104 106 100
Miguel - 88 86 89 93 105
Adam's 50% range = 106 - 100
= 6
Miguel's 50% range = 105 - 86
= 19
Adam has the least spread
C. Miguel is inconsistent with the time set for training compared to that of Adam.
The answers to parts 2a and 2b show that there is a wide variation in the time that Miguel spend during training, but a minimum variation in the time spent by Adam during training.