Answer:
J=-50
Step-by-step explanation:
If we expand bx to jx and kx we have:
5y^2-2y-7
5y^2-7y+5y-7 then factor...
y(5y-7)+1(5y-7)
(y+1)(5y-7)
So the other factor is:
(y+1)
Answer:
x=0 x=3 x=-2
Step-by-step explanation:
p(x)= 3x^3 – 3x^2– 18x
Factor out the greatest common factor, 3x
p(x)= 3x (x^2 – x– 6)
Factor inside the parentheses
What 2 numbers multiplies to -6 and adds to -1
-3*2 = -6
-3+2 = -1
p(x)= 3x (x-3)(x+2)
Setting the function equal to zero to find the zeros
0 = 3x (x-3)(x+2)
Using the zero product property
3x = 0 x-3 =0 x+2 =0
x=0 x=3 x=-2