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Setler [38]
3 years ago
15

Mathematics A private post -secondary corporation has 1 year low stock price of $18.69 and high price of $40.47.Assume that you

bought it at the lowest price and sold it at highest price.what is simple rate of return on stock purchase.
a.)116.533%
b.)106.712%
C.)107.812%
D.)107.612%
Mathematics
1 answer:
laila [671]3 years ago
7 0

Answer:

Step-by-step explanation:

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How do you divided 14.28 /4.2
Rufina [12.5K]
You dived 14.28/4.2 by taking the decimal out and when you get the answer put it back
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3 years ago
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Suppose the parent population has an exponential distribution with a mean of 15 and standard deviation of 12. Use the Central Li
bazaltina [42]

Answer:

The sampling distribution of the sample mean of size 30 will be approximately normal with mean 15 and standard deviation 2.19.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For the population, we have that:

Mean = 15

Standard deviaiton = 12

Sample of 30

By the Central Limit Theorem

Mean 15

Standard deviation s = \frac{12}{\sqrt{30}} = 2.19

Approximately normal

The sampling distribution of the sample mean of size 30 will be approximately normal with mean 15 and standard deviation 2.19.

4 0
3 years ago
00:00
vlada-n [284]

Volume of the cylinder is 480 cm³ (rounded off to the nearest tenth)

Step-by-step explanation:

  • Step 1: Find volume of the cylinder when radius = 4 cm and height = 9.5 cm

Volume = πr²h = 3.14 × 4² × 9.5

             = 3.14 × 16 × 9.5 = 477.28 cm³ ≈ 480 cm³

3 0
2 years ago
A study is performed in San Antonio to determine whether the average weekly grocery bill per five-person family in the town is s
bogdanovich [222]

Answer:

No, the sample evidence is not statistically significant (P-value = 0.125).

To reject the null hypothesis, the P-value has to be smaller than the significance level, so the significance level to reject the null hypothesis has to be 0.125 or higher.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the average weekly grocery bill per five-person family in San Antonio is significantly different from the national average.

Then, the null and alternative hypothesis are:

H_0: \mu=131\\\\H_a:\mu\neq 131

The significance level is 0.05.

The sample has a size n=50.

The sample mean is M=133.474.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=11.193.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{11.193}{\sqrt{50}}=1.583

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{133.474-131}{1.583}=\dfrac{2.474}{1.583}=1.563

The degrees of freedom for this sample size are:

df=n-1=50-1=49

This test is a two-tailed test, with 49 degrees of freedom and t=1.563, so the P-value for this test is calculated as (using a t-table):

P-value=2\cdot P(t>1.563)=0.125

As the P-value (0.125) is bigger than the significance level (0.05), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the average weekly grocery bill per five-person family in San Antonio is significantly different from the national average.

8 0
2 years ago
Switch row 2 and row 3:
Natali [406]

Answer:

-2,3,1,-2

8,-4,6,30

Step-by-step explanation:

4 0
2 years ago
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