9514 1404 393
Answer:
rectangle: 2x+2 wide by 2x high
triangle: 2 high
Step-by-step explanation:
Usually, a problem like this is asking you to find dimension expressions that combine to give you the given expression. There are usually a number of possibilities. Using the designators in the attached, we would generally like to have B > C and A about the same as C. That doesn't seem possible with the given factors.
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The given quadratic expression factors as ...
area = 4x^2 +6x +2 = (2x+2)(2x +1)
This might be written to match the area formula as ...
(2x +2)(2x +2/2)
This would give A=2, B=2x+2, C=2x, as shown in the attachment.
Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
1 is ur answer Step-by-step explanation:
Answer:Sub C = 75 in to your equation.: C=20
F= (9/5)X75 + 32
Step-by-step explanation:
