There is : 3 pencils
4 Bubble gums
2 sports cards
In each favor bag
Answer:
100
Step-by-step explanation:
We have the sum of first n terms of an AP,
Sn = n/2 [2a+(n−1)d]
Given,
36= 6/2 [2a+(6−1)d]
12=2a+5d ---------(1)
256= 16/2 [2a+(16−1)d]
32=2a+15d ---------(2)
Subtracting, (1) from (2)
32−12=2a+15d−(2a+5d)
20=10d ⟹d=2
Substituting for d in (1),
12=2a+5(2)=2(a+5)
6=a+5 ⟹a=1
∴ The sum of first 10 terms of an AP,
S10 = 10/2 [2(1)+(10−1)2]
S10 =5[2+18]
S10 =100
This is the sum of the first 10 terms.
Hope it will help.
Midpoint of (a,b,c) and (e,f,g) is
((a+e)/2,(b+f)/2,(c+g)/2)
just average them
the x value
(2+-2)/2=0/2=0
the y value
(-2+0)/2=-2/2=-1
the z value
(4+6)/2=10/2=5
(0,-1,5) is da midopint
WHATS THE QUESTION i can’t help if there’s no question
Answer:
Step-by-step explanation:
<h3>Can I have the brainliest please?</h3>
