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Margarita [4]
3 years ago
8

Who want to help me out

Mathematics
1 answer:
Readme [11.4K]3 years ago
4 0

Answer:

A, B, and C

Step-by-step explanation:

Since there are no right angles, 89 is too close to 90 which is a right angles (which there are no angles even close to 90) and 94 would be too large since all angles are less than 90 degrees.

You might be interested in
Solve the value of y for the given values of x: 4x = 3y - 7; x= 4,5,6
julia-pushkina [17]
Thhe easiest way would be to solve for y first
4x=3y-7
add 7
4x+7=3y
divide both sides by 3
(4x+7)/3=y

try each
x=4
(4(4)+7)/3=y
(16+7)/3=y
(23)/3=y
7 and 2/3=y
(4,7.66666)


x=5
(4(5)+7)/3=y
(20+7)/3=y
(27)/3=y
9=y
(5,9)

x=6
(4(6)+7)/3=y
(24+7)/3=y
(31)/3=y
10 and 1/3=y
(6,10.333)



(4,7.66666)
(5,9)
(6,10.333)

when x=4, y=7 and 2/3
when x=5, y=9
when x=6, y=10 and 1/3



5 0
3 years ago
Read 2 more answers
What is the simplify of this expression -2(2b-3)
patriot [66]

-2(2b-3)

Multiply the bracket by -2

Whenever multiplying a -negative number with a -negative number= + positive number.

(-2)(2b)(-2)(-3)

-4b+6

Answer: -4b+6

6 0
4 years ago
Read 2 more answers
A scale drawing of a school bus has a scale of 12 inch to 5 feet. If the length of the school bus is 412 inches on the scale dra
sattari [20]

Answer: Actual length of the bus = 171.67 feet

Width of the lake on the scale drawing = 12.5 inches

Step-by-step explanation:

Given : A scale drawing of a school bus has a scale of 12 inch to 5 feet.

i.e. 12 inch = 5 feet

\Rightarrow \text{ 1 inch}=\dfrac{5}{12}\text{ feet}

If length of school bus on scale drawing = 412 inches

Then, Actual length of bus = \dfrac{5}{12}\times412=171.67\ \text{feet}

A scale drawing of a lake has a scale of 1 cm to 80 m.

If the actual width of the lake is 1,000 m

then, the width of the lake on the scale drawing = \dfrac{1000}{80}=12.5\text{ inches}

8 0
4 years ago
Suppose you need to get the dent in your car fixed. You see the ads in the newspaper above (mikes repair shop $100 service charg
Norma-Jean [14]

Answer:

<em>Total Cost at Amy's shop is $280 which is less than the total cost at Mike's shop which is $295, so I will take the car to Amy's shop</em>

<em>Point of intersection: (x,y) = (4,360)</em>

Explanation:

Part 1 )

Let x = number of hours worked

Let y = total cost to you

Determining where to take the car:

<em>Total Cost at Amy's shop is $280 which is less than the total cost at Mike's shop which is $295</em>

Mike's repair shop:

Service fee: $100

Per hour rate: $65

Let x is the number of hours worked on. Total cost will be equal to the service fee plus hourly charges. Charges per an hour are $65, so for x hours the charges will be 65x.

Therefore, total cost for Amy's repair shop can be written as:

y = 100 + 65x ------(1)

For 3 hours work: y = 100 + 65(3)

<em>Cost at Mike's, y = $100 + $195 = $295</em>


<em>Amy's repair shop: </em>

Service fee: $40

Per hour rate: $80

Charges per an hour are $40, so for x hours the charges will be 80x.

Therefore, total cost for Amy's repair shop can be written as:

y = 40 + 80x ------(2)

For 3 hours work: x = 3

y = 40 + 80(3)

<em>Cost at Amy's, y  = $40 + $240 = $280</em>


<em>Part 2)</em>

<em>Find the point of intersection</em>

<em>Using elimination method:</em>

<em>y = 100 + 65 x    ------1</em>

<em>y = 40 + 80x      ------2</em>

<em>As the y coefficients are equal we will subtract eq1 from eq2</em>

<em>y - y = 40 + 80x - 100 - 65x</em>

<em>0 = -60 + 15x</em>

60 = 15x

x = \frac{60}{4}

x = 4

put x = 4 in eq 1

we get y = 100 + 65 (4) = 100 + 260 = 360

x = 4, y = 360

Point of intersection: (x,y) = (4,360)



8 0
4 years ago
The floor plan of a factory is dilated by a factor of 4 to create a new, larger floor plan.
Flura [38]

The original floor could be rectangle in shape.

If we consider the length of floor to be 'L' and width of floor to be 'W',

then area of original floor = length x width = LW.

And if its dimensions are dilated by scale factor of 4 to make new floor, then new length and width would become four times of older values. So new length would be '4L' and new width would be '4W'

Now area of new floor = length x width = 4L x 4W = 16LW.


It is clear that the area of new floor is 16 times of the area of original floor.

So, option C i.e. 16 is the final answer.

7 0
4 years ago
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