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2 years ago

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Brendon had total job benefits of $39,500 last year. He was required to wear a shirt with the company logo on it for work that h

e was responsible for buying. Brendon purchased 12 shirts for work during the year at a cost of $23. 95 each. He was also required to attend a training at a cost to him of $135. What was Brendon’s total employment compensation last year? a. $39,077. 60 b. $39,212. 60 c. $39,341. 05 d. $39,922. 40 Please select the best answer from the choices provided A B C D.

2 answers:

san4es73 [151]2 years ago

6 0

Answer:

A

Step-by-step explanation:

It is correct

Ierofanga [76]2 years ago

5 0

Answer:

It's B

Step-by-step explanation:

If u grab the job benefits and multiply the cost of the shirt 12 times and then minus the cost of the training it will give you the answer B.

Brainliest

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Find the value of xxx in the triangle shown below. Choose 1 answer: Choose 1 answer: (Choice A) A x=\sqrt{21}x= 21 x, equals,

Keith_Richards [23]

Answer:

x = 15.8114

Step-by-step explanation:

The complete question is:

"The problem is asking for value of x. Two right triangles side by side, the altitude is 9. The bottom of whole triangle is 25. One side is 15 and the other side is x. What is the value of x?"

Solution:-

- Develop a diagram for the information given " Two right triangles side by side" The altitude i.e height (common to both triangle ) = 9. The total base length of both triangles is = 25. One side is 15 and other side is x.

x

x x x

x x x

x x x

x x x x = ?

x x x

15 x x x

x x 9 x

x x x

x x x

x x x

x x x

x x x

B x x x x x x x x x x x x x x x x x x x x x x x C

y D 25-y

- We will first determine the value of "y" using the left hand side triangle and apply pythagorean theorem. Where, H = 15 , P = 9 , B = y.

H^2 = P^2 + B^2

15^2 = 9^2 + y^2

y = √(225 - 81 )

y = 12

- Now we can use the value of y and apply pythagorean theorem on right hand side triangle with sides. H = x , P = 9 , B = 25-y = 25 - 12 = 13.

H^2 = P^2 + B^2

x^2 = 9^2 + 13^2

x = √( 81 + 169 )

x = 15.8114

3 0

3 years ago

Read 2 more answers

Suppose you do not know the population mean fee charged to H&R Block customers last year. Instead, suppose you take a sample

puteri [66]

Answer:

i $\to$ a

$n = 96040000$

i $\to$ b

$n_1 =24010000$

i $\to$ c

$n_2 =41602500$

ii $\to$ a

$E = 58.16$

ii $\to$ b

$291.84 < \mu < 408.16$ \

ii $\to$ c

There is insufficient evidence to conclude that the analyst is right because the population mean fee by the analyst does not fall within the confidence interval

Step-by-step explanation:

From the question we are told that

The sample size is $n = 8$

The sample mean is $\= x = \$ 350$

The sample standard deviation is $\$ 100$

Considering question i

i $\to$ a

At $E = 0.02$

given that the confidence level is 95% = 0.95

the level of significance would be $\alpha =1-0.95 = 0.05$

The critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{ \alpha }{2} } = 1.96$

So the sample size is mathematically evaluated as

$n = [ \frac{Z_{\frac{\alpha }{2} } * \sigma }{E} ]^2$

=> $n =[ \frac{ 1.96 * 100}{ 0.02} ]^2$

=> $n = 96040000$

i $\to$ b

At $E_1 = 0.04$ and confidence level = 95% => $\alpha_1 = 0.05$ => $Z_{\frac{\alpha_1 }{2} } = 1.96$

$n_1 = [ \frac{Z_{\frac{\alpha_2 }{2} } * \sigma }{E_1} ]^2$

=> $n_1 =[ \frac{ 1.96 * 100}{ 0.04} ]^2$

=> $n_1 =24010000$

i $\to$ c

At $E_2 = 0.04$ confidence level = 99% => $\alpha_2 = 0.01$

The critical value of $\frac{\alpha_2 }{2}$ from the normal distribution table is

$Z_{\frac{ \alpha_2 }{2} } = 2.58$

=> $n_2 = [ \frac{Z_{\frac{\alpha_2 }{2} } * \sigma }{E_2} ]^2$

=> $n_2 =[ \frac{ 2.58 * 100}{ 0.04} ]^2$

=> $n_2 =41602500$

Considering ii

Given that the level of significance is $\alpha = 0.10$

Then the critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

substituting values

$E = 1.645 * \frac{100 }{\sqrt{8} }$

$E = 58.16$

Generally the 90% confidence interval is mathematically evaluated as

$\= x - E < \mu < \= x + E$

=> $350 - 58.16 < \mu < 350 + 58.16$

=> $291.84 < \mu < 408.16$

So the interpretation is that there is 90% confidence that the mean fee charged to H&R Block customers last year is in the interval .So there is insufficient evidence to conclude that the analyst is right because the population mean fee by the analyst does not fall within the confidence interval.

8 0

3 years ago

How are the graphs<br> of f(x) = x2 and g(x) = -(x + 2)2 - 4<br> related?

Effectus [21]

g(x) is f(x) shifted 4 units down and 2 units to the left and flipped over the x-axis.

6 0

3 years ago

What is the exact volume of a cylinder with a base height of 30, and a radius of 13

Tcecarenko [31]

Volume of a cylinder is $\pi$ $r^{2}$ h. This is basically the area of a circle multiplied by the height. You can think of it as congruent circles being stacked on top of each other to create a cylinder. With the given information, all we have to do is substitute the values into the variables

V = $\pi$ $r^{2}$ h.
V = $\pi$ $(13)^{2}$ x30
V = $\pi$ x 169 x 30 = $\pi$ 5070

Hope this helps!
(btw if it asks for "exact" anything, leave the pi. Pi is the ratio of the circumference to its diameter, so not every circle will have a pi of 3.14.)

3 0

3 years ago

Could someone help me with this pls

barxatty [35]

Answer:

7.99

Step-by-step explanation:

using the formula

$v = \pi \: r ^{2} h$

$3014.4 = 22 \div 7 \times r ^{2} \times 15$

$21100.8 = 22 \times 15 \times r {}^{2}$

$21100.8 = 330 \times r {}^{2}$

$21100.8 \div 330 = r {}^{2}$

$\sqrt{63.94 }= r$

$r = 7.99ft \: answer$

8 0

2 years ago