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3 years ago

11

Jack can text 210 characters in 21 minutes. Write an expression for m minutes.

1 answer:

Oduvanchick [21]3 years ago

4 0

The answer is B 210m

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Which of the following is in the solution set of y< 8 x− 3? Select one: (7, 46) (7, 60) (10, 89) (9, 82)

navik [9.2K]

Answer:

(7, 46)

Step-by-step explanation:

The offered answer choices have x-values of 7, 9, 10. The corresponding upper limit of y-value is ...

x=7 : y < 8·7 -3 = 53 . . . . . 46 is in the solution set, 60 is not

x=9 : y < 8·9 -3 = 69 . . . . 82 is not in the solution set

x=10 : y < 8·10 -3 = 77 . . . . 89 is not in the solution set

Of the choices offered, only (7, 46) is in the solution set.

3 0

3 years ago

What are the solutions of the equation (2x + 3)2 + 8(2x + 3) + 11 = 0

Tom [10]

Answer:

$x=\frac{-7-\sqrt{5}}{2}$ or $x=\frac{-7+ \sqrt{5}}{2}$

Step-by-step explanation:

The given equation is

$(2x+3)^2+8(2x+3)+11=0$

Let us treat this as a quadratic equation in $(2x+3)$ .

where $a=1,b=8,c=11$

The solution is given by the quadratic formula;

$(2x+3)=\frac{-b\pm \sqrt{b^2-4ac} }{2a}$

We substitute these values into the formula to obtain;

$(2x+3)=\frac{-8\pm \sqrt{8^2-4(1)(11)} }{2(1)}$

$(2x+3)=\frac{-8\pm \sqrt{64-44} }{2}$

$(2x+3)=\frac{-8\pm \sqrt{20} }{2}$

$(2x+3)=\frac{-8\pm2\sqrt{5} }{2}$

$(2x+3)=-4\pm \sqrt{5}$

$(2x+3)=-4-\sqrt{5}$ or $(2x+3)=-4+ \sqrt{5}$

$2x=-3-4-\sqrt{5}$ or $2x=-3-4+ \sqrt{5}$

$2x=-7-\sqrt{5}$ or $2x=-7+ \sqrt{5}$

$x=\frac{-7-\sqrt{5}}{2}$ or $x=\frac{-7+ \sqrt{5}}{2}$

5 0

3 years ago

(n 4 - 2n 3 - 3n 2 + 7n - 2) ÷ (n - 2)

GrogVix [38]

I believe it's

- 1 - $\frac{4}{n - 2}$

Hope I helped! ( Smiles )

7 0

3 years ago

Read 2 more answers

Using fraction busting solve for X <br><br>1/x² + 1/x = 6/x²

777dan777 [17]

The solution for this question would be. x += 5 hope it helps, and im truly am sorry if its incorrect!

8 0

2 years ago

Find the zeros of the function g(x) = x2 - 6x - 16 by factoring. what is the largest zero of the function? enter a number only.

aleksandrvk [35]

(X-8)(x+2) is the factored equation. Ur zeros r -2 and 8. So the largest should be 8?

5 0

3 years ago