Solution-
Let, total number of t-shirts sold by Ashley= x
since, she made $3 for each t-shirt.
therefore, total profit made by selling x t-shirts= $3x
therefore, Net Profit= (Total Profit made by selling t-shirts)- (total expenditure)
$51=$3x-$27
∴ $3x= $51+$27=$78
∴x =$78/$3=26
Therefore, Ashley needs to sell total 26 t-shirts in order to make a profit of $51.
Answer:
The coordinates I chose are (0,-5) and (2,-4)
Step-by-step explanation:
Part A = 4 1/8 im pretty sure
Answer:
<em>f(0)>f(1) and f(1)<f(2), therefore a critical point exists at f(1). As the value is greater before the critical point and is greater after as well, thus there exists a local minima at x=1.</em>
<em>f(3) <f(4) and f(4)>f(5), therefore a critical point exists at f(4). As the value is less before the critical point and is less after as well, thus there exists a local maxima at x=4.</em>
Step-by-step explanation:
As the data table is missing in the question, a similar question is found, which is as attached here with.
From the data of table
x | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
----------------------------------------------------
y=f(x) | -3 | -5 | -4 | -1 | 2 | 1 | -1 | -3 | -4 | -6 | -7 |
From the graph attached the critical points are as given below
As
<em>f(0)>f(1) and f(1)<f(2), therefore a critical point exists at f(1). As the value is greater before the critical point and is greater after as well, thus there exists a local minima at x=1.</em>
<em>f(3) <f(4) and f(4)>f(5), therefore a critical point exists at f(4). As the value is less before the critical point and is less after as well, thus there exists a local maxima at x=4.</em>