Answer:
13,800
Step-by-step explanation:
Answer:
pretty sure its B
Step-by-step explanation:
X = -10
Y = 8
2 X + 3 Y = 4 ---- (i)
5 X + 4 Y + 13 = 0 ---- (ii)
rearranging eqn (ii), we have
5X + 4Y = -13 ----- (ii)
multiply eqn (i) by 5 and eqn (ii) by 2
10X + 15Y = 20 ---- (iii)
10X + 8Y = -26 ---- (iv)
subtracting eqn (iv) from (iii), we have
10X - 10X + 15Y - 8Y = 20 - (-26)
0 + 7Y = 20 + 26
7Y = 56
Y = 56/7
Y = 8
Substituting Y into eqn (i), we have
2X + 3Y = 4
2X + 3(8) = 4
2X + 24 = 4
2X = 4 - 24
2X = -20
X = -20/2
X = -10
Answer:
The answer is
to the
over
power
Step-by-step explanation:
we know that
![\sqrt[n]{a^{m}} =a^{\frac{m}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5E%7Bm%7D%7D%20%3Da%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D)
In this problem we have
![\sqrt[4]{7^{5}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B7%5E%7B5%7D%7D)
so
![\sqrt[4]{7^{5}} =7^{\frac{5}{4}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B7%5E%7B5%7D%7D%20%3D7%5E%7B%5Cfrac%7B5%7D%7B4%7D%7D)