Please help me with these accounting questions
1 answer:
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Answer:
cyclical unemployment.
Explanation:
Unemployment rate refers to the percentage of the total labor force in an economy, who are unemployed but seeking to be gainfully employed. The unemployment rate is divided into various types, these include;
I. Cyclical unemployment rate (CU).
II. Frictional unemployment rate (FU).
III. Structural unemployment rate (SU).
IV. Actual unemployment rate (AU).
V. Natural Rate of Unemployment (NU).
A cyclical unemployment can be defined as a type of unemployment which is typically related to changes in the business, economy or industry cycle such as recession, governmental policies etc.
Mathematically, cyclical unemployment rate can be calculated using the formula;
Hence, the increase in unemployment that occurs during recessions and depressions is called cyclical unemployment
Answer:
a. Debit to Prepaid Insurance of $10,000
* Option for this question was missing so I have attached a similar question with this answer and answered accordingly.
Explanation:
Insurance purchased for four years was actually prepaid insurance on May 1, Year 2.
The company expensed all amount by positing following entry ( which is a wrong entry)
DR. Insurance Expense $12,000
Cr. Cash $12,000
It should be entered as follow:
DR. Prepaid Insurance $12,000
Cr. Cash $12,000
At the end of the year 2 8 months has been passed for which $2,000 is accrued and it will be recorded, as all the amount is charged to the expense account we will adjusted the remaining amount of $10,000 to correct this mistake.
Now at the end of year 2 the correct entry which will settle the expense and prepaid insurance as well is as follow.
DR. Prepaid Insurance $10,000
Cr. Insurance Expense $10,000
Answer:
They should operate Mine 1 for 1 hour and Mine 2 for 3 hours to meet the contractual obligations and minimize cost.
Explanation:
The formulation of the linear programming is:
Objective function:
Restrictions:
- High-grade ore:
- Medium-grade ore:
- Low-grade ore:
- No negative hours:
We start graphing the restrictions in a M1-M2 plane.
In the figure attached, we have the feasible region, where all the restrictions are validated, and the four points of intersection of 2 restrictions.
In one of this four points lies the minimum cost.
Graphically, we can graph the cost function over this feasible region, with different cost levels. When the line cost intersects one of the four points with the lowest level of cost, this is the optimum combination.
(NOTE: it is best to start with a low guessing of the cost and going up until it reaches one point in the feasible region).
The solution is for the point (M1=1, M2=3), with a cost of C=$680.
The cost function graph is attached.
