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polet [3.4K]
3 years ago
6

Hola busco nva si quieres ​

Mathematics
2 answers:
LenKa [72]3 years ago
7 0

Answer:

buena suerte ojala encuentres

lora16 [44]3 years ago
3 0

Answer:

Step-by-step explanation:

Buena suerte con ella

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(2x^9y^n) (4x²y^10)-8x^11 y^20                        i say the answer 1 or 10

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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4 0
2 years ago
I really don’t get it!!
AleksAgata [21]

Answer:

The answer is b.

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8 0
3 years ago
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Hope it helps <3

7 0
4 years ago
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{ \underline{ \sf{true}}}

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