Answer:
The number of adults tickets and student tickets purchased is 5 and 3.
Given that,
Tickets to a movie cost $7.25 for adults and $5.50 for students.
A group of friends purchased 8 tickets for $52.75.
Here we assume the no of adult tickets and no of student tickets be x and y.
Based on the above information, the calculation is as follows:
7.25x + 5.50y = 52.75 .............(i)
x + y = 8
x = 8 - y..................(2)
Now put the x value in the equation (1)
So,
7.25(8-y) + 5.50y = 52.75
7.25 × 8 - 7.25y + 5.50y = 52.75
58 - 1.75y = 52.75
5.25 = 1.75y
y = 3
So,
x = 8 - 3
= 5
Therefore we can conclude that the number of adults tickets and student tickets purchased is 5 and 3.
-Hope this helps<3
Answer:
I can try
Step-by-step explanation:
Answer:
- 12 ft parallel to the river
- 6 ft perpendicular to the river
Step-by-step explanation:
The least fence is used when half the total fence is parallel to the river. That is, the shape of the rectangle is twice as long as it is wide.
72 = W(2W)
36 = W²
6 = W . . . . . . the width perpendicular to the river
12 = 2W . . . . the length parallel to the river
_____
<em>Development of this relation</em>
Let T represent the total length of the fence for some area A. Then if x is the length along the river, the width is y=(T-x)/2, and the area is ...
A = xy = x(T -x)/2
Note that the equation for area is that of a parabola with zeros at x=0 and at x=T. That is, for some fence length T, the area will be a maximum at the vertex of this parabola. That vertex is located halfway between the zeros, at ...
x = (0 +T)/2 = T/2
The corresponding area width (y) is ...
y = (T -T/2)/2 = T/4
Equivalently, the fence length T will be a minimum for some area A when x=T/2 and y=T/4. This is the result we used above.
Y = kx
when y= 12, x=3
12 = 3k
k = 12/3
k = 4
y = 4x
when x= 15
y = 4(15)
y = 60
