Let's use the addition/subtraction method.
Suppose we wish to eliminate variable x.
Mult the first eqn by 5: 10x - 15y = 15
Mult the 2nd eqn by -2: -10x+ 4y = -8
Add these two equations together: -11y = 7, and y = -7/11.
Subst. -7/11 for y in either given equation and find x.
Then your solution is (x,y) (subst. the values we've found for x and y).
Answer:
a = 6, b = 8, and c = 10.
Step-by-step explanation:
You can easily use the Pythagorean Theorem to solve all of these.
a = 4; b = 6; c = 8... 4^2 + 6^2 = 16 + 36 = 52. 8^2 = 64. 52 is not equal to 64, so the first choice is not a right triangle.
a = 6; b = 8; c = 10... Well this is a multiple of the 3-4-5 Pythagorean triple, so this is a right triangle.
a = 5; b = 6; c = 761... 5^2 + 6^2 = 25 + 36 = 61. 761^2 = 579121, which is not equal to 61, so the third choice is not a right triangle.
a = 6; b = 9; c = 12... 6^2 + 9^2 = 36 + 81 = 117. 12^2 = 144, which is not equal to 117, so the fourth choice is not a right triangle.
The only case where there is a right triangle is the second choice, where a = 6, b = 8, and c = 10.
Hope this helps!
Answer:
490
Step-by-step explanation:
