The len ( ) function will run with each iteration, printing the element number each time.
Answer:
- import java.util.Arrays;
- public class Main {
-
- public static void main(String[] args) {
- String [] first = {"David", "Mike", "Katie", "Lucy"};
- String [] middle = {"A", "B", "C", "D"};
- String [] names = makeNames(first, middle);
-
- System.out.println(Arrays.toString(names));
- }
-
- public static String [] makeNames(String [] array1, String [] array2){
-
- if(array1.length == 0){
- return array1;
- }
-
- if(array2.length == 0){
- return array2;
- }
-
- String [] newNames = new String[array1.length];
-
- for(int i=0; i < array1.length; i++){
- newNames[i] = array1[i] + " " + array2[i];
- }
-
- return newNames;
- }
- }
Explanation:
The solution code is written in Java.
Firstly, create the makeNames method by following the method signature as required by the question (Line 12). Check if any one the input string array is with size 0, return the another string array (Line 14 - 20). Else, create a string array, newNames (Line 22). Use a for loop to repeatedly concatenate the string from array1 with a single space " " and followed with the string from array2 and set it as item of the newNames array (Line 24-26). Lastly, return the newNames array (Line 28).
In the main program create two string array, first and middle, and pass the two arrays to the makeNames methods as arguments (Line 5-6). The returned array is assigned to names array (Line 7). Display the names array to terminal (Line 9) and we shall get the sample output: [David A, Mike B, Katie C, Lucy D]
Answer:
Pretty sure it's concentration camps
Answer:
C communication software
Explanation:
C communication software IS THE ANSWER
Answer:
rita should either ask the original author for permission to use her blog, but the best answer woyuld be that she should site her sources.
Explanation:
