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bekas [8.4K]
3 years ago
8

The use of computers to combine data from multiple sources and create electronic dossiers of detailed information on individuals

is called a. profiling. b. phishing. c. spamming. d. targeting.
Computers and Technology
1 answer:
pantera1 [17]3 years ago
5 0
A.Profiling! Hope this helps
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Suppose that in a 00-11 knapsack problem, the order of the items when sorted by increasing weight is the same as their order whe
frosja888 [35]

Answer:

Following are the response to the given question:

Explanation:

The glamorous objective is to examine the items (as being the most valuable and "cheapest" items are chosen) while no item is selectable - in other words, the loading can be reached.

Assume that such a strategy also isn't optimum, this is that there is the set of items not including one of the selfish strategy items (say, i-th item), but instead a heavy, less valuable item j, with j > i and is optimal.

As W_i < w_j, the i-th item may be substituted by the j-th item, as well as the overall load is still sustainable. Moreover, because v_i>v_j and this strategy is better, our total profit has dropped. Contradiction.

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3 years ago
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Brrunno [24]

Answer:

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Explanation:

5 0
3 years ago
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In three to five sentences, describe how you would move a slide from the end of the presentation to the second slide.
hjlf
You just hold on the slide you want to move and move it to the second slide.
3 0
2 years ago
Write a program that uses the function strcmp() to compare two strings input by the user. The program should state whether the f
Andru [333]

user_str1 = str ( input ("Please enter a phrase: "))

user_str2 = str ( input("Please enter a second phrase: "))

def strcmp (word):

user_in1 = int (len(user_str1))

user_in2 = int (len(user_str2))

if user_in1 > user_in2:

return "Your first phrase is longer"

elif user_in1 < user_in2:

return "Your second phrase is longer"

else:

return "Your phrases are of equal length"

3 0
3 years ago
I have six nuts and six bolts. Exactly one nut goes with each bolt. The nuts are all different sizes, but it’s hard to compare t
juin [17]

Answer:

Explanation:

In order to arrange the corresponding nuts and bolts in order using quicksort algorithm, we need to first create two arrays , one for nuts and another for bolts namely nutsArr[6] and boltsArr[6]. Now, using one of the bolts as pivot, we can rearrange the nuts in the nuts array such that the nuts on left side of the element chosen (i.e, the ith element indexed as nutArr[i]) are smaller than the nut at ith position and nuts to the right side of nutsArr[i] are larger than the nut at position "I". We implement this strategy recursively to sort the nuts array. The reason that we need to use bolts for sorting nuts is that nuts are not comparable among themselves and bolts are not comparable among themselves(as mentioned in the question)

The pseudocode for the given problem goes as follows:

// method to quick sort the elements in the two arrays

quickSort(nutsArr[start...end], boltsArr[start...end]): if start < end: // choose a nut from nutsArr at random randElement = nutsArr[random(start, end+1)] // partition the boltsArr using the randElement random pivot pivot = partition(boltsArr[start...end], randElement) // partition nutsArr around the bolt at the pivot position partition(nutsArr[start...end], boltsArr[pivot]) // call quickSort by passing first partition quickSort(nutsArr[start...pivot-1], boltsArr[start...pivot-1]) // call quickSort by passing second partition quickSort(nutsArr[pivot+1...end], boltsArr[pivot+1...end])

// method to partition the array passed as parameter, it also takes pivot as parameter

partition(character array, integer start, integer end, character pivot)

{

       integer i = start;

loop from j = start to j < end

       {

check if array[j] < pivot

{

swap (array[i],array[j])

               increase i by 1;

           }

 else check if array[j] = pivot

{

               swap (array[end],array[j])

               decrease i by 1;

           }

       }

swap (array[i] , array[end])

       return partition index i;

}

7 0
3 years ago
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