You take away the 4 from the 8 which is equal to 4 then you have to barrow from the 2 to make the 4 to 14 and when you wait you are basically right your calculation is right
0.36363636363 = 0.36363636363/1 = 3.6363636363/10 = 36.363636363/100 = 363.63636363/1000 = 3636.3636363/10000 = 36363.636363/100000 = 363636.36363/1000000 = 3636363.6363/10000000 = 36363636.363/100000000 = 363636363.63/1000000000 = 3636363636.3/10000000000 = 36363636363/100000000000 the answer is
0.36363636363 as a fraction equals 36363636363/100000000000
Answer:
312°
Step-by-step explanation:
PSQ = 360°- mPAQ
at mPAQ=mSAR
so PSQ =360°-48°=312°
Answer:
Step-by-step explanation:
If the liquid is cooling at a constant rate, then the equation for this is linear. We can use the info given to find the linear equation for this situation. We have 2 points: (2, 178) and (5, 154), where the x coordinate represents the time in minutes, and y represents the temperature. We use these values in the slope formula:
Now we will use one of the points to finish writing the equation. I chose (2, 178), but it doesn't matter which one you choose; they will both give you the same equation in the end.
y - 178 = -8(x - 2) and
y - 178 = -8x + 16 so
y = -8x + 196
If we are looking for the temp when the liquid starting cooling, then we are looking for the temp at time 0, or when x = 0 (sincce x is our time).
y = -8(0) + 196 so
y = 196
That's the temp of the liquid before it started any cooling.