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Oksana_A [137]
2 years ago
6

A ratio of 10 to 2 is the same as A 8/2 B 8/10 C 12/8 D 5/1​

Mathematics
1 answer:
kati45 [8]2 years ago
6 0

Answer:

D. 5/1

Step-by-step explanation:

10/2 = 5

5/1 = 5

I hope this helps :)

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Identify the ellipses, represented by equations, whose eccentricities are less than 0.5
ozzi

Answer:

See explanation

Step-by-step explanation:

Hello, we cannot see the ellipse equations.

The eccentric of an ellipse is given by:

e =  \frac{c}{a}

Assuming the equations are:

\frac{ {x}^{2} }{25}  +  \frac{ {y}^{2} }{16}  = 1

Then a²=25 and b²=16

{c}^{2}  =  {a}^{2}  -  {b}^{2}

{c}^{2}  = 25 - 16

{c}^{2}  =  {3}^{2}

c = 3

The eccentricity is:

e =  \frac{3}{5}  = 0.6

If the ellipse has equation,

\frac{ {x}^{2} }{ {5}^{2} }  +  \frac{ {y}^{2} }{ {3}^{2} }  = 1

then the this time, we have a=5 and b=3.

This means that:

{c}^{2}  =  {a}^{2}  -  {b}^{2}

{c}^{2}  =  {5}^{2}  -  {3}^{2}

{c}^{2}  =  {4}^{2}

c = 4

c =  \frac{4}{5}  = 0.8

3 0
3 years ago
Read 2 more answers
Please help the picture is
asambeis [7]

The walls are vertical so the angle opposite X would be a right angle which is 90 degrees.

X would be 180 - 90 - 35 = 55 degrees

X and 2y - 5 are complementary angles which add together to equal 90:

2y - 5 + 55 = 90

Simplify:

2y +50 = 90

Subtract 50 from both sides:

2y = 40

Divide both sides by 2:

y = 20

7 0
3 years ago
Read 2 more answers
im not sure on how to do this If one angle of a triangle is 30° more than twice another angle, and the third angle is equal to t
deff fn [24]

Answer:

Step-by-step explanation: How do you find the 3rd angle of a triangle?

Image result for im not sure on how to do this If one angle of a triangle is 30° more than twice another angle, and the third angle is equal to the sum of the first two angles, find the measure of each angle.

The three angles of any triangle add up to 180 degrees. Since you know two angles (35 and 40), add them together, then subtract the total from 180 to determine the degree of the third angle.

4 0
2 years ago
Solve for x. leave your answer in simplest radical form.
adell [148]

Answer:

could you provide the equation for which x is to be solved?:)...If your question was supposed to be that ...then hope the solution helps:)

8 0
1 year ago
2) 83,97,85,84,96, 80,80,87,91<br> Mean median and mode
marusya05 [52]

\text {Hi! Let's Solve this Problem!}

\text {Before you find the Mean, Medina and Mode you must put the numbers in order.}

\text {Before: 83, 97, 85, 84, 96, 80, 80, 87, 91}\\\text {After: 80, 80, 83, 84, 85, 87, 91, 96, 97}

\underline {\text {Mean}}

\text {To Find the Mean you must Add all the Numbers then Divide.}

\text {Add:} \text 80+80+83+84+85+87+91+96+97=\fbox {783}}

\text {Divide:} \text {783/9=}

\text {The Mean Is:}

\fbox {87}

\underline {\text Median}}

\text {To find the Median you find the number that's in the middle of the set.}

\text {Put your Left Pointer Finger on 83. Put your Right Pointer Finger on 91.}

\text {Move your Left Finger to the Right. Move your Right Finger to the Left.}

\text {Once your Left Finger makes it to 84 and your Right Finger makes it to 87} \text {it shows that 85 is left in the middle.}

\text {The Median Is:}

\fbox {85}

\underline {\text {Mode}}

\text {Finding the Mode means finding the number} \text { that shows the most in the number set given.}

\text {Since 80 is the number that is showing more than any other number} \text {this tells us that 80 is our Mode.}

\text {The Mode Is:}

\fbox {80}

\text {Best of Luck!}

4 0
3 years ago
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