3 years ago

GUYS PLEASE HELP ME OUT WITH THIS ONE QUESTION.

Mathematics

1 answer:

bazaltina [42]3 years ago

3 0

Answer: A&R is X-3 R&E are 5 B&C are parallel

Step-by-step explanation:

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Step 1: Pick any two points

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where x1= -4, y1= -8, x2= 0, y2= 4

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Step 3: Substituting the values and to get the equation

$\begin{gathered} \frac{y-(-8)_{}}{x-(-4)}=\text{ }\frac{4-(-8)}{0-(-4)} \\ \frac{y+8}{x+4}=\frac{4+8}{0+4} \\ \frac{y+8}{x+4}=\text{ }\frac{12}{4} \end{gathered}$ $\begin{gathered} \frac{y+8}{x+4}=\text{ 3} \\ \text{Cross multiply} \\ y+8=\text{ 3(x+4)} \\ y+8=\text{ 3x+12} \\ \text{Collect like terms} \\ y=\text{ 3x+12-8} \\ y=\text{ 3x + 4} \end{gathered}$

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