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2 years ago

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The soccer team played 7 games and scored the following number goals in each game: 2, 1, 3, 5, 3, 1, 4. What was the median numb

er of goals the team scored for the seven games? goals

2 answers:

Travka [436]2 years ago

7 0

Answer:

3

Step-by-step explanation:

first put them in order

1 1 2 3 3 4 5

then cancel them down go from the front to the back so go like

1 then 5 then 1 again then 4 and etc

u would then end up with the last two numbers which is 3 and 3. if u had numbers like 5 and 7 u would have to find the number in the middle of which would be 6. in the case the two numbers you are left with is 3 and 3 since there both the same the answer would be 3

hope this helped :)

soldi70 [24.7K]2 years ago

6 0

Hey there!

Median number :-

Given numbers are

2,1,3,5,3,1,4

Arranging in ascending order,

1,1,2,3,3,4,5

Median = 3

Hope this helps :)

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Arrange 88,667 132,414 23,112 83,001 to smallest to largest

Zanzabum

Answer:

001,23,83,88,112,132,667

Step-by-step explanation:

Are you kidding me that you need help on this?

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3 years ago

Read 2 more answers

The average cost of living for a family of four in twelve different cities was found to be $65,351 with a standard deviation of

Andrej [43]

Answer:

$65,351+/-$3,661.73

= ( $61,689.27, $69,012.73)

Therefore, the 90% confidence interval (a,b) = ( $61,689.27, $69,012.73)

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = $65,351

Standard deviation r = $7,711

Number of samples n = 12

Confidence interval = 90%

z(at 90% confidence) = 1.645

Substituting the values we have;

$65,351+/-1.645($7,711/√12)

$65,351+/-1.645($2,225.973962860)

$65,351+/-$3661.727168905

$65,351+/-$3,661.73

= ( $61,689.27, $69,012.73)

Therefore, the 90% confidence interval (a,b) = ( $61,689.27, $69,012.73)

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3 years ago

Which correctly describes how the graph of the inequality 6y − 3x > 9 is shaded? -Above the solid line

baherus [9]

The statement which correctly describes the shaded region for the inequality is $\fbox{\begin\\\ Above the dashed line\\\end{minispace}}$

Further explanation:

In the question it is given that the inequality is $6y-3x>9$ .

The equation corresponding to the inequality $6y-3x>9$ is $6y-3x=9$ .

The equation $6y-3x=9$ represents a line and the inequality $6y-3x>9$ represents the region which lies either above or below the line $6y-3x=9$ .

Transform the equation $6y-3x=9$ in its slope intercept form as $y=mx+c$ , where $m$ represents the slope of the line and $c$ represents the $y$ -intercept.

$y$ -intercept is the point at which the line intersects the $y$ -axis.

In order to convert the equation $6y-3x=9$ in its slope intercept form add $3x$ to equation $6y-3x=9$ .

$6y-3x+3x=9+3x$

$6y=9+3x$

Now, divide the above equation by $6$ .

$\fbox{\begin\\\math{y=\dfrac{x}{2}+\dfrac{1}{2}}\\\end{minispace}}$

Compare the above final equation with the general form of the slope intercept form $\fbox{\begin\\\math{y=mx+c}\\\end{minispace}}$ .

It is observed that the value of $m$ is $\dfrac{1}{2}$ and the value of $c$ is $\dfrac{3}{2}$ .

This implies that the $y$ -intercept of the line is $\dfrac{3}{2}$ so, it can be said that the line passes through the point $\fbox{\begin\\\ \left(0,\dfrac{3}{2}\right)\\\end{minispace}}$ .

To draw a line we require at least two points through which the line passes so, in order to obtain the other point substitute $0$ for $y$ in $6y=9+3x$ .

$0=9+3x$

$3x=-9$

$\fbox{\begin\\\math{x=-3}\\\end{minispace}}$

This implies that the line passes through the point $\fbox{\begin\\\ (-3,0)\\\end{minispace}}$ .

Now plot the points $(-3,0)$ and $\left(0,\dfrac{3}{2}\right)$ in the Cartesian plane and join the points to obtain the graph of the line $6y-3x=9$ .

Figure $1$ shows the graph of the equation $6y-3x=9$ .

Now to obtain the region of the inequality $6y-3x>9$ consider any point which lies below the line $6y-3x=9$ .

Consider $(0,0)$ to check if it satisfies the inequality $6y-3x>9$ .

Substitute $x=0$ and $y=0$ in $6y-3x>9$ .

$(6\times0)-(3\times0)>9$

$0>9$

The above result obtain is not true as $0$ is not greater than $9$ so, the point $(0,0)$ does not satisfies the inequality $6y-3x>9$ .

Now consider $(-2,2)$ to check if it satisfies the inequality $6y-3x>9$ .

Substitute $x=-2$ and $y=2$ in the inequality $6y-3x>9$ .

$(6\times2)-(3\times(-2))>9$

$12+6>9$

$18>9$

The result obtain is true as $18$ is greater than $9$ so, the point $(-2,2)$ satisfies the inequality $6y-3x>9$ .

The point $(-2,2)$ lies above the line so, the region for the inequality $6y-3x>9$ is the region above the line $6y-3x=9$ .

The region the for the inequality $6y-3x>9$ does not include the points on the line $6y-3x=9$ because in the given inequality the inequality sign used is $>$ .

Figure $2$ shows the region for the inequality $\fbox{\begin\\\math{6y-3x>9}\\\end{minispace}}$ .

Therefore, the statement which correctly describes the shaded region for the inequality is $\fbox{\begin\\\ Above the dashed line\\\end{minispace}}$

Learn more:

A problem to determine the range of a function brainly.com/question/3852778
A problem to determine the vertex of a curve brainly.com/question/1286775
A problem to convert degree into radians brainly.com/question/3161884

Answer details:

Grade: High school

Subject: Mathematics

Chapter: Linear inequality

Keywords: Linear, equality, inequality, linear inequality, region, shaded region, common region, above the dashed line, graph, graph of inequality, slope, intercepts, y-intercept, 6y-3x=9, 6y-3x>9, slope intercept form.

4 0

3 years ago

Read 2 more answers

Fill in the steps to solve the log log base x of (2x)^3=6

arsen [322]

Answer:

x=2

Step-by-step explanation:

logx (2x)^3 = 6

We can rewrite without the exponent

3 logx (2x) = 6

Divide by 3

3/3 logx (2x) = 6/3

logx (2x) = 2

Raise each side to the base x

x^ logx (2x) =x^ 2

2x = x^2

Subtract 2x from each side

2x-2x = x^2 -2x

0 = x^2 -2x

Factor an x

0 = x(x-2)

Using the zero product property

x =0 x-2 =0

x =0 x=2

We cannot have a base of 0, so x cannot equal 0

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3 years ago

BRAINLYYYY PLUS 100 PointsThe difference between two numbers is 84 and their sum is 278. What are the numbers? Hint( answer is x

den301095 [7]

Answer:

x = 181 and y = 97

Step-by-step explanation:

let called the first number is x

the second number would be called y

We are given that:

x + y = 278 (1)

x = y + 84 (2)

Let change x in (2) into (1):

y + 84 + y = 278

2y + 84 = 278

Subtract 84 from both side, we got:

2y + 84 - 84 = 278 - 84

2y + 0 = 194

Divide both side by 2, we got:

2y / 2 = 194 / 2

y = 97

Because y = 97 and x + y = 278 so x would equal:

x + 97 = 278

Subtract 97 from both side, we got:

x + 97 - 97 = 278 - 97

x + 0 = 181

x = 181 and y = 97

Hope this helped :3

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3 years ago