Question

What is an equation of the line that passes through the points (8, -8) and (1, 6)?

Answer 1

Answer:

$y=-2x+8$

Step-by-step explanation:

In slope-intercept form, the equation of a line is given by $y=mx+b$, where $m$ is the slope of the line, $b$ is the y-intercept, and $(x,y)$ represent the coordinates of any point the line passes through.

Since we're given two points the line passes through, we can find the slope of the line using the slope formula $m=\frac{\Delta y}{\Delta x}$:

$m=\frac{-8-6}{8-1}=\frac{-14}{7}=-2$

Now we can plug in any point the line passes through to find the y-intercept:

$6=-2(1)+b,\\6=-2+b,\\b=8$

Thus, the equation of this line is equal to $y=-2x+8$.