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3 years ago

What is an example illustrating gravitational potential energy transforming into kinetic energy?

Physics

1 answer:

Bess [88]3 years ago

7 0

Answer:

A. a hammer dropped off a roof accelerates as it falls.

Explanation:

The example that illustrates gravitational potential energy transforming into kinetic energy is a hammer dropped off a roof accelerating as it falls.

Gravitational potential energy is the energy due to the position of a body.

A hammer held up at roof level has a measure of gravitational potential energy.

As it drops and begins to accelerate, the energy is converted to kinetic energy. Kinetic energy is the energy due to the motion of a body.

The acceleration due to gravity causes the body to move.

So, the gravitational potential energy is converted to kinetic energy.

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Which charateristic of the observant function?

valentina_108 [34]

Answer:

All people with the observant trait are often a steadying force that always wants to get things done. Their energy is very elegant in the sense of working on real things in real time.

Explanation:

Hope I helped

8 0

2 years ago

Please Help Meee.. Will give brainlest

anygoal [31]

Answer:

Total resistance is 19.6 Ω for the circuit .

Explanation:

Given:

Six resistors of a circuit namely $R_1$ to $R_6$ .

Where

$R_1$ and $R_2$ are in series.

$R_3$ and $R_4$ are in parallel.

$R_5$ and $R_6$ are in parallel.

We know that continuous resistor which are in series are added up to find the equivalent resistance.

Similarly resistors which are arranged in parallel their equivalent resistance is $\frac{R_3R_5}{R_3+R_5}$ for the case of $R_3$ and $R_5$ .

According to the question:

Total resistance = R(equivalent) :

⇒ $R_(eq_) = R_1+R_2+(\frac{R_3R_4}{R_3+R_4} )+(\frac{R_5R_6}{R_5+R_6} )$

⇒ $R_(eq_)=7+8+(\frac{4\times 6}{4+6} )+(\frac{3\times 8}{3+8} )$

⇒ $R_(eq_)=7+8+(\frac{24}{10} )+(\frac{24}{11} )$

⇒ $R_(eq_)=15+(2.4 )+(2.18)$

⇒ $R_(eq_)=19.58$ Ω

So the total resistance of the circuit depicted is 19.58 Ω approximated to nearest tenth that is 19.6 Ω

6 0

4 years ago

Please answer it I will mark it brainliest

Margaret [11]

Explanation:

1) If you spot something you think might be hazardous in your workplace, report it to your employer and safety rep straight away. Your employer should then decide what harm the hazard could cause and take action to eliminate, prevent or reduce that harm. Read more about risk assessments .

2) Complex hazards are understood as various combinations of sources of hazards that lead to the accident occurrences. ... The term "natural-technological" applies to both human-induced intensification of natural risks and any accidents in the technosphere triggered by natural processes or phenomena.

3)Risk Evaluation : To determine who may be harmed. Risk Control : Taking preventive measures to control the impact of risk.

In general, to do an assessment, you should:

Identify hazards.

Determine the likelihood of harm, such as an injury or illness occurring, and its severity. ...

Identify actions necessary to eliminate the hazard, or control the risk using the hierarchy of risk control methods.

5 0

2 years ago

Read 2 more answers

A motorbike travels 45 miles in 15 minutes, what is its speed (hint change the minutes to hours!!)

Flauer [41]

Answer:

180 miles/hr

Explanation:

15 min=1/4 hr

s= distance/time

s=45miles/1/4 hr

s=45miles x 4/1=180 miles/hr

6 0

3 years ago

Suppose that the voltage across the resistor is held constant at 40 volts. If the resistance is steadily decreasing at a rate of

hjlf

Answer:

The current is increasing at a rate of 0.32 ampere per second.

Explanation:

The voltage of the resistor is modelled after Ohm's Law, which states that voltage is directly proportional to current:

$V = i\cdot R$ (1)

Where:

$V$ - Voltage, measured in volts.

$i$ - Current, measured in amperes.

$R$ - Resistance, measured in ohms.

An expression for the rate of change in voltage is found by Differential Calculus:

$\frac{dV}{dt} = \frac{di}{dt}\cdot R +i\cdot \frac{dR}{dt}$

$\frac{dV}{dt} = \frac{di}{dt}\cdot R + \frac{V}{R}\cdot \frac{dR}{dt}$ (2)

Where:

$\frac{dV}{dt}$ - Rate of change in voltage, measured in volts per second.

$\frac{di}{dt}$ - Rate of change in current, measured in amperes per second.

$\frac{dR}{dt}$ - Rate of change in resistance, measured in ohms per second.

If we know that $\frac{dV}{dt} = 0\,\frac{V}{s}$ , $R = 5\,\Omega$ , $V = 40\,\Omega$ and $\frac{dR}{dt} = -0.2\,\frac{\Omega}{s}$ , then the rate of change in current is:

$5\cdot \frac{di}{dt}-1.6 = 0$ (3)

$\frac{di}{dt} = 0.32\,\frac{A}{s}$

The current is increasing at a rate of 0.32 ampere per second.

5 0

3 years ago