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klio [65]
3 years ago
15

Which of the following is the most likely end for a star that formed from a very small nebular cloud? . . Black hole . . Planeta

ry nebula . . Red supergiant . . Supernova .
Physics
1 answer:
vekshin13 years ago
8 0
The answer for this question would be Planetary Nebula.

Black holes are created when the star core has a mass of more than 2.5 times of the Sun. In Supernova, fo<span>r stars with mass of more than 8 times the mass of the Sun, death is signalled by a gigantic explosion: during the first second it can be as bright as a whole galaxy with hundreds of billions of stars. In Red Giants, it is </span>due to explosion of average stars like the Sun. Lastly, in Planetary Nebula, f<span>or small stars (that is less than 8 times the mass of the Sun), at the end of the Red Giant phase, the star can’t contract enough to generate the temperatures needed for further nuclear fusion.</span>
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What type of circuit has little or no resistance?
lions [1.4K]

Answer: A. short circuit

Explanation:

7 0
4 years ago
Read 2 more answers
Which is an example of transforming potential energy to kinetic energy? Select two options.
Rasek [7]

<u>Complete Question:</u>

Which is an example of transforming potential energy to kinetic energy? Select two options.

changing thermal energy to electrical energy

changing chemical energy to thermal energy

changing nuclear energy to radiant energy

changing radiant energy to electrical energy

changing mechanical energy to chemical energy

<u>Correct Answer:</u>

The examples of transforming potential energy to kinetic energy are changing chemical energy to thermal energy and changing nuclear energy to radiant energy.

<u>Explanation:</u>

As stated by the conservation of energy law, any form of energy is usually transferred to another form. The basic kinds of energy is potential and kinetic energy. Potential energy is the energy stored for the objects at rest and kinetic energy is the energy utilized by the objects for motion.

So in the given options, chemical energy is the energy stored by the chemical bonds to make a stable compound and that energy is converted to thermal energy when the bonds get broken. So the stored energy or the energy required to keep the bonds intact is chemical energy and it is thus a form of potential energy.

And when these bonds get broken, the electrons use the thermal energy released by this breakage as their kinetic energy. So one form of transforming potential energy to kinetic energy is by changing chemical energy to thermal energy.

Similarly, the nuclear energy is exhibited by the elementary particles in an atom. So it is similar to potential energy and the radiant energy is released whenever there is an excitation. So the radiant energy will be similar to kinetic energy.

Thus, the changing of chemical energy to thermal energy and the changing of nuclear energy to radiant energy are the examples of transforming potential energy to kinetic energy.

5 0
3 years ago
An object was thrown at a certain angle above the ground.It reaches a maximum height of 42.50 meters and hits back the ground 76
aksik [14]

Answer:

Explanation:  Please see my attached calculations.

7 0
3 years ago
A ball is thrown up onto a roof, landing 4 sec later at height of 20m above the release level. The balls path just before landin
Kobotan [32]
<span>c) what is the angle (relative to the horizontal) of the balls initial velocity? </span>
8 0
3 years ago
Calculate the de Broglie wavelength of an electron accelerated from rest through a potential difference of (a) 100 V, (b) 1.0 kV
forsale [732]

Answer:

(a) \lambda=1.227\ A

(b) \lambda=0.388\ A

(c) \lambda=0.038\ A

Explanation:

Given that,

(a) An electron accelerated from rest through a potential difference of 100 V. The De Broglie wavelength in terms of potential difference is given by :

\lambda=\dfrac{h}{\sqrt{2meV} }

Where

m and e are the mass of and charge on an electron

On solving,

\lambda=\dfrac{12.27}{\sqrt{V} }\ A

V = 100 V

\lambda=\dfrac{12.27}{\sqrt{100} }\ A

\lambda=1.227\ A

(b) V = 1 kV = 1000 V

\lambda=\dfrac{12.27}{\sqrt{V} }\ A

\lambda=\dfrac{12.27}{\sqrt{1000} }\ A

\lambda=0.388\ A

(c) If V=100\ kV=10^5\ V

\lambda=\dfrac{12.27}{\sqrt{10^5} }\ A

\lambda=0.038\ A

Hence, this is the required solution.

7 0
3 years ago
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