The gradient for a parallel line is the same.
perpendicular lines are negative reciprocals.
so all you have to do is re arrange it so y=Mx+b so the check out the gradients to what I listed above... remember y shouldn't have any number on it.
(5-2/x)/4-3/x^2
after simplifying these
(5x-2)/x(4x^2-3)/x^2
x(5x-2)/(4x^2-3)
5x^2-2x/4x^2-3
now u can solve it
Answer:
the answer is a
Step-by-step explanation:
if you compare pm and qn pm is shorter so you see its only a little bit longer then that so its close to there.