Answer:
4 moles of NH3 will be produced
Explanation:
The reaction expression is given as:
N₂ + 3H₂ → 2NH₃
We have to check that the equation of the reaction is balanced.
Then;
if 2 mole of N₂ reacts;
1 mole of N₂ will react with 3 mole of H₂ to produce 2 mole of NH₃
2 mole of N₂ will react with (2x3)mole of H₂ to produce (2x2)mole of NH₃
6mole of H₂ to produce 4 mole of NH₃
Answer:
The new volume of the gas is 21 L.
Explanation:
Volume of a gas is inversely proportional to its pressure at constant temperature such that,
or
We have,
It is required to find V₂. Using above law or Boyle's law such that :
So, the new volume of the gas is 21 L.
Once for the water and once for the copper. Set up a table that accounts for each of the variables you know, and then identify the ones you need to obtain. Give me a moment or two and I will work this out for you.
Okay, so like I said before, you will need to use the equation twice. Now, keep in mind that when the copper is placed in the water (the hot into the cold), there is a transfer of heat. This heat transfer is measured in Joules (J). So, the energy that the water gains is the same energy that the copper loses. This means that for your two equations, they can be set equal to each other, but the copper equation will have a negative sign in front to account for the energy it's losing to the water.
When set equal to each other, the equations should resemble something like this:
(cmΔt)H20 = -(cmΔt)Cu
(Cu is copper).
Remember, Δt is the final temperature minus the initial temperature (T2-T1). We are trying to find T2. Since we are submerging the copper into the water, we can assume that the final temperature at equilibrium is the same for both the copper and the water. At a thermodynamic equilibrium, there is no heat transfer because both materials are at the same temperature.
T2Cu = T2H20
Now, the algebra for this part of the problem is a bit confusing, so make sure you keep track of your variables. If done right, the algebra should work out so you have this:
T2 = ((cmT1)Cu + (cmT1)H20) / ((cm)H20 + (cm)Cu)
Insert the values for the variables. Once you plug and chug, your final answer should be
26.8 degrees Celsius.
Answer:
Solution Density of aluminium = 2.7 g/Cm 3 In kg/ m 3 = 27 × 1000 10 =2700 kg/ m 3
Explanation:
Not much of one
