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pentagon [3]
3 years ago
6

The process of moving water from its source to places where humans use it is called water diversion. true or false

Chemistry
1 answer:
MAXImum [283]3 years ago
6 0

Answer:

That is def true

Explanation:

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A 5.50 gram sample of C2H6 gas has a volume of 2.50 L. If the sample is at 41.20C, what will it’s pressure be?
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Multiple them divided by 2.50
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A wave of infrared light has a speed of 6 m/s and a wavelength of 12 m. What is the frequency of this wave?
andreev551 [17]

Answer: The frequency of the wave is 0.5 hertz.

Explanation:

\nu =\frac{c}{\lambda }

\nu = Frequency of the wave

c = speed of the light in m/s

\lambda = Wavelength of the wave.

Here in question we are given with speed of the infrared light. So, we will replace the value of speed of light(c) from the given value of the speed of the infrared light.

Speed of infrared light = 6 m/s

\nu =\frac{\text{speed of infrared light}}{\lambda }=\frac{6 m/s}{12 m}=0.5 hertz

The frequency of the wave is 0.5 hertz.


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If 0.50 mol/L of butane is added to the original equilibrium mixture and the system shifts to a new equilibrium position, what i
Ostrovityanka [42]

Consider the isomerization of butane with equilibrium constant is 2.5 .The system is originally at equilibrium with :

[butane]=1.0 M , [isobutane]=2.5 M

If 0.50 mol/L of butane is added to the original equilibrium mixture and the system shifts to a new equilibrium position, what is the equilibrium concentration of each gas?

Answer:

The equilibrium concentration of each gas:

[Butane] = 1.14 M

[isobutane] = 2.86 M

Explanation:

Butane  ⇄  Isobutane

At equilibrium

1.0 M               2.5 M

After addition of 0.50 M of butane:

(1.0 + 0.50) M               -

After equilibrium reestablishes:

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The equilibrium expression will wriiten as:

K_c=\frac{[Isobutane]}{[Butane]}

2.5=\frac{2.5+x}{(1.50-x)}

x = 0.36 M

The equilibrium concentration of each gas:

[Butane]= (1.50-x) = 1.50 M - 0.36M = 1.14 M

[isobutane]= (2.5+x) = 2.50 M + 0.36 M = 2.86 M

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