1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jeyben [28]
3 years ago
11

Percent composition?: 85.05 g of Mg combines completely with 112.21 g of S.

Chemistry
1 answer:
hammer [34]3 years ago
5 0

Empirical Formula = C20 H60 HG1 S1 O4 (numbers should be in subscript)

Percent Composition =

MG = 43%

S = 56.8%

You might be interested in
What is the meaning of the word solubility
LekaFEV [45]
Amount of a substance (called the solute) that dissolves in a unit volume of a liquid substance (called the solvent) to form a saturated solution under specified conditions of temperature and pressure.Solubility is expressed usually as moles of solute per 100 grams of solvent.
3 0
3 years ago
Read 2 more answers
10.0 g Cu, C Cu = 0.385 J/g°C 10.0 g Al, C Al = 0.903 J/g°C 10.0 g ethanol, Methanol = 2.42 J/g°C 10.0 g H2O, CH2O = 4.18 J/g°C
Mazyrski [523]

Answer:

Lead shows the greatest temperature change upon absorbing 100.0 J of heat.

Explanation:

Q=mc\Delte T

Q = Energy gained or lost by the substance

m = mass of the substance

c = specific heat of the substance

ΔT = change in temperature

1) 10.0 g of copper

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the copper = c =  0.385 J/g°C

\Delta T=\frac{Q}{mc}

=\frac{100.0 J}{10 g\times 0.385J/g^oC}=25.97^oC

2) 10.0 g of aluminium

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the aluminium= c =  0.903 J/g°C

\Delta T=\frac{Q}{mc}

=\frac{100.0 J}{10 g\times 0.903 J/g^oC}=11.07^oC

3) 10.0 g of ethanol

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the ethanol= c =  2.42 J/g°C

\Delta T=\frac{Q}{mc}

=\frac{100.0 J}{10 g\times 2.42 J/g^oC}=4.13 ^oC

4) 10.0 g of water

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the water = c =  4.18J/g°C

\Delta T=\frac{Q}{mc}

=\frac{100.0 J}{10 g\times 4.18 J/g^oC}=2.39 ^oC

5) 10.0 g of lead

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the lead= c =  0.128 J/g°C

\Delta T=\frac{Q}{mc}

=\frac{100.0 J}{10 g\times 0.128 J/g^oC}=78.125^oC

Lead shows the greatest temperature change upon absorbing 100.0 J of heat.

3 0
3 years ago
In a chemical reaction, the difference between the potential energy of the products and the potential energy of the reactants is
vova2212 [387]

Answer:

4. the heat of reaction

5 0
3 years ago
All matter has thermal energy because atoms are constantly
ololo11 [35]
The atoms are constantly in motion
3 0
3 years ago
The pressure on 30 milliliters of an ideal gas increases from
Nana76 [90]

V1 = 30 mL

P1 = 760 torr

P2 = 1520 torr

V2 = ?

applying Boyle's Law

P1*V1 = P2*V2

760 torr * 30 mL = 1520 torr * V2

V2 = 760 torr * 30 mL / 1520 torr

( C ) is correct

8 0
3 years ago
Other questions:
  • Is Mika souring chemical or physical
    12·1 answer
  • What is the chemical formula of this organic compound
    15·1 answer
  • Pressure is the force exerted by a substance on its container. Of the three phases of matter which one would exert the highest p
    10·1 answer
  • Chemical equation for hydrogen chloride dissolving in water
    14·1 answer
  • how much water must be added when 125 mL of a 2.00 M solution of HCl is diluted to a final concentration of 0.400M?
    8·2 answers
  • A gas sample has volume 3.00 dm3 at 101
    10·1 answer
  • HELP PLS EEEEEEEEEEEEEEEEEEEE
    8·2 answers
  • Write the balanced half equation of iron 2 and permanganate in a solution of acid. Show all of your work.
    15·1 answer
  • 30 POINTS!! Will mark brainliest if correct answer and all work is shown! What mass in grams of tin would be required to complet
    14·1 answer
  • Swimming pool structures and structural _____ [680.26(B)(1) and (B)(2)] shall not be used as a grounding electrode.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!