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jeyben [28]
3 years ago
11

Percent composition?: 85.05 g of Mg combines completely with 112.21 g of S.

Chemistry
1 answer:
hammer [34]3 years ago
5 0

Empirical Formula = C20 H60 HG1 S1 O4 (numbers should be in subscript)

Percent Composition =

MG = 43%

S = 56.8%

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BARSIC [14]

The number of C atoms in 0.524 moles of C is 3.15 atoms.

The number of SO_2 molecules in 9.87 moles  SO_2 is 59.43 molecules.

The moles of Fe in 1.40 x 10^{22} atoms of Fe is 0.23 x 10^{-1}

The moles of C_2H_6O in 2.30x10^{24} molecules of C_2H_6O is 3.81.

<h3>What are moles?</h3>

A mole is defined as 6.02214076 × 10^{23} of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

A. The number of C atoms in 0.524 mole of C:

6.02214076 × 10^{23} x 0.524 mole

3.155601758 atoms =3.155 atoms

B. The number of SO_2 molecules in 9.87 moles of SO_2:

6.02214076 × 10^{23} x 9.87

59.4385293 molecules= 59.43 molecules

C. The moles of Fe in 1.40 x 10^{22} atoms of Fe:

1.40 x 10^{22} ÷ 6.02214076 × 10^{23}

0.2324754694 x 10^{-1} moles.

0.23 x 10^{-1} moles.

D. The moles of C_2H_6O in 2.30x10^{24} molecules of C_2H_6O:

2.30x10^{24} ÷ 6.02214076 × 10^{23}

3.819239854 moles=3.81 moles

Learn more about moles here:

brainly.com/question/8455949

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6. protons, mass number from the atomic number

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when the following redoc reaction is balances (assume acidic solution), how many moles of water appear and on what side
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8 moles of water on the right side.

An oxidation-reduction or redox reaction is a reaction that involves the transfer of electrons between chemical items (the atoms, ions, or molecules involved in the reaction).

Redox reactions: the burning of fuels, the corrosion of metals, and even the processes of photosynthesis and cellular respiration involve oxidation and reduction.

Step 1:

MnO4- ----> Mn2+

2Cl- ------> Cl2

Step 2:

MnO4- --> Mn2+ + 4H2O

2Cl- -----> Cl2

Step 3:

8H+ + MnO4- ------> Mn2+ + 4H2O

2Cl- ----->Cl2

Step 4:

8H+ + MnO4- +5e- ------>Mn2+ + 4H2O

2Cl- ----> Cl2+ 2e-

Step 5:

16 H+ +2 MnO4- +10Cl- ----->2 Mn2+ + 8H2O+5Cl2

This is the balanced equation in an acidic medium.

That is 8, right side.

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