Reflect across the x-axis. Then rotate the shape around point B' 120 degrees clockwise.
1 answer:
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Answer:
see below
Step-by-step explanation:
Reflection across the x-axis just changes the signs of the y-coordinates. Rotation -120° about B' is difficult to do by hand. The transformation rule for that is ...
(x, y) ⇒ (x·cos(-120°) +y·sin(-120°), -x·sin(-120°) +y·cos(-120°))
(x, y) ⇒ ((-(x-3) +(y+2)√3)/2 +3, (-(x-3)√3 -(y+2))/2 -2)
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It looks like your problem is presented in GeoGebra, which makes reflection and rotation easy.
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Answer:
m∠R = 60°
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u> </u>
<u>Trigonometry</u>
- [Right Triangles Only] SOHCAHTOA
- [Right Triangles Only] sinθ = opposite over hypotenuse<u> </u>
Step-by-step explanation:
<u>Step 1: Identify</u>
Angle θ = ∠R
Opposite Leg of ∠R = 10√3
Hypotenuse = 20
<u>Step 2: Solve</u>
- Substitute in variables [sine]:
- [Equality Property] Trig inverse:
- Evaluate trig: