M(Pb(C2H5)4 = M(PB)*1 + 4*( M(C)*2 + M(H)*5)
M(Pb(C2H5)4 = 207.2 + 4(12.0*2 + 1.0*5)
M(Pb(C2H5)4 = 207.2 + 4(28.0 + 5)
M(Pb(C2H5)4 = 207.2 + 4*33
M(Pb(C2H5)4 = 207.2 + 132
M(Pb(C2H5)4 = 339.2 g/mol

Hope this helps !

Photon

4 0

4 years ago

Juan pulled a red card from the deck of regular playing cards. This probability is 2652 or 12 . He puts the card back into the d

kenny6666 [7]

Answer:

Step-by-step explanation:

if he randomly pulls it out it's still the same number of red cards and also the total number of cards as always

can't change

6 0

3 years ago

Read 2 more answers

Hey motorcycle shop maintains an inventory of four times as many new bikes as used bikes. If there are 16 new bikes how many use

nlexa [21]

Motorcycle shop maintains

U - used bikes
N - new bikes = 4N

1 U = 4N
? U = 16 new bikes

16/4 = 4. There are 4 used bikes that are in stock.

7 0

4 years ago

Read 2 more answers

A rectangle has a length that is 5 meters greater than the width. If w represents the width, write an expression, in terms of w,

ahrayia [7]

Answer:

Area of rectangle is $w^2+5w$

Perimeter of Rectangle is $4w+20$ .

Step-by-step explanation:

Given:

Let the width of the rectangle be 'w'.

Also Given:

A rectangle has a length that is 5 meters greater than the width.

Length of rectangle = $w+5\ meters$

We need to write expression for Area of rectangle and Perimeter of rectangle.

Solution:

Now we know that;

Perimeter of rectangle is equal to twice the sum of the length and width.

framing in equation form we get;

Perimeter of rectangle = $2(w+5+w)=2(2w+5) =4w+20$

Also We know that;

Area of rectangle is length times width.

framing in equation form we get;

Area of rectangle= $w(w+5) = w^2+5w$

Hence Area of rectangle is $w^2+5w$ and Perimeter of Rectangle is $4w+20$ .

6 0

3 years ago