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kvasek [131]
3 years ago
9

PLS HELP!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
avanturin [10]3 years ago
6 0
The answer it the second on <2=<8
Alexandra [31]3 years ago
4 0
B because of the corresponding angles therom
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Last one! Pls anyone?
BARSIC [14]

Ai whish i can help but idk

Step-by-step explanation:

5 0
2 years ago
4. A store had 86 DVDs and 52 CDs. When the equal number of DVDs and CDs were sold,
11Alexandr11 [23.1K]

Answer:

51 DVDs

Step-by-step explanation:

Let the number of DVDs and CDs sold be x each.

<u>Initial</u>

Number of DVDs= 86

Number of CDs= 52

<u>After selling</u>

Number of DVDs= 86 -x

Number of CDs= 52 -x

Given that there are 3 times as many DVDs than CDs left,

86 -x= 3(52 -x)

<em>Expand:</em>

86 -x= 156 -3x

<em>Bring x terms to 1 side, constant to the other:</em>

3x -x= 156 -86

<em>Simplify:</em>

2x= 70

<em>Divide both sides by 2:</em>

x= 35

Amount of DVDs left

= 86 -x

= 86 -35

= 51

3 0
3 years ago
Find constants a and b such that the function y = a sin(x) + b cos(x) satisfies the differential equation y'' + y' − 5y = sin(x)
vichka [17]

Answers:

a = -6/37

b = -1/37

============================================================

Explanation:

Let's start things off by computing the derivatives we'll need

y = a\sin(x) + b\cos(x)\\\\y' = a\cos(x) - b\sin(x)\\\\y'' = -a\sin(x) - b\cos(x)\\\\

Apply substitution to get

y'' + y' - 5y = \sin(x)\\\\\left(-a\sin(x) - b\cos(x)\right) + \left(a\cos(x) - b\sin(x)\right) - 5\left(a\sin(x) + b\cos(x)\right) = \sin(x)\\\\-a\sin(x) - b\cos(x) + a\cos(x) - b\sin(x) - 5a\sin(x) - 5b\cos(x) = \sin(x)\\\\\left(-a\sin(x) - b\sin(x) - 5a\sin(x)\right)  + \left(- b\cos(x) + a\cos(x) - 5b\cos(x)\right) = \sin(x)\\\\\left(-a - b - 5a\right)\sin(x)  + \left(- b + a - 5b\right)\cos(x) = \sin(x)\\\\\left(-6a - b\right)\sin(x)  + \left(a - 6b\right)\cos(x) = \sin(x)\\\\

I've factored things in such a way that we have something in the form Msin(x) + Ncos(x), where M and N are coefficients based on the constants a,b.

The right hand side is simply sin(x). So we want that cos(x) term to go away. To do so, we need the coefficient (a-6b) in front of that cosine to be zero

a-6b = 0

a = 6b

At the same time, we want the (-6a-b)sin(x) term to have its coefficient be 1. That way we simplify the left hand side to sin(x)

-6a  -b = 1

-6(6b) - b = 1 .... plug in a = 6b

-36b - b = 1

-37b = 1

b = -1/37

Use this to find 'a'

a = 6b

a = 6(-1/37)

a = -6/37

8 0
2 years ago
Which trigonometric functions have the same maximum value?
svlad2 [7]
The maximum value of the function is M = A + |B|. This maximum value occurs whenever sin x = 1 or cos x = 1.
3 0
3 years ago
Which is greater
olga55 [171]
They are even/equal
(please mark brainliest)
5 0
2 years ago
Read 2 more answers
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