Find roots of the equation and state the multiplicity

Mathematics

1 answer:

olya-2409 [2.1K]3 years ago

7 0

$({x + 2})^{3} = {x}^{3} + 6 {x}^{2} + 12x + 8$
so the answer is
$x = - 2$

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Pythagorean Theorem to solve for x. If the hypnoses is 10 m, and one leg is 6 m. Find the other leg x

lilavasa [31]

Answer:

The other leg X = 8m

Step-by-step explanation:

As per Pythagorean theorem-

Square of hypotenuse = sum of square of other two sides of the triangle

Substituting the given values in above equation, we get -

$10^2 = 6^2 + X^2\\100 - 36 = X^2\\X^2 = 64\\X = 8$ m

The other leg X = 8m

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3 years ago

Please help with these 3 questions and show all work!

Bas_tet [7]

Question 1:
"Match" the letters
DE are the last two letters of BCDE
The last two letters of OPQR is QR
DE is congruent to QR

Question 2:
Blank 3: Reflexive property (shared side)
Blank 4: SSS congruence of triangles (We have 3 sets of congruent sides)

Question 3:
I'm guessing those two numbers are 7.
Since both are 7, AB and AE are congruent.
We know that all the other sides are congruent because it is given.
We also know that there is a congruent angle in each triangle.
Thus, the two triangles are congruent by SAS or SSS.
(Note: I couldn't prove this without the two "7"s because there is no such thing as SSA congruence)

Have an awesome day! :)

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Answer:

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Step-by-step explanation: