Ax + c = R (subtract c from each side)
Ax + c - c = R - c
Ax = R - c (divide A from each side)
Ax/A = (R-c)/A
x = 
<-answer
Erm
x+y=6
xy=12
x+y=6
y=6-x
sub back
xy=12
x(6-x)=12
6x-x^2=12
x^2-6x=-12
x^2-6x+12=0
quadratic formula
for
ax²+bx+c=0

for
x²-6x+12=0
a=1
b=-6
c=12
and remember that √-1=i






x=3+/-i√3
the numbers are 3+i√3 and 3-i√3
no real numbers tho
No, because the sum of two sides must be larger than the third.
Answer:
10,1
Step-by-step explanation:
Answer:
18 in
Step-by-step explanation:
First you would multiply 2·5=10 then for the area of the bottom shape you already have 4 for one side to get the other side you subtract 7-5 and get 2 so 4·2=8 so then add the areas of both shapes and get 18