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3 years ago

A statement that is true both forwards and backwards is called a?

2 answers:

wel3 years ago

8 0

A statement that is true both forwards and backwards. That is the original statement and its converse are both true.

spin [16.1K]3 years ago

6 0

A Bi-Conditional Statement - A statement that is true both forwards and backwards. That is the original statement and its converse are both true-

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Pablo spit 3/4 pounds of candy amping 4 people what is the unit rate in pounds per person

Sunny_sXe [5.5K]

The unit rate is $\frac{3}{16}$ pounds per person.

Step-by-step explanation:

Given,

Quantity of candy Pablo have = $\frac{3}{4}$ pounds

Number of people = 4

We will divide the Quantity of candy by number of people.

Quantity of candy per person = $\frac{3}{4}*\frac{1}{4}$

Quantity of candy per person = $\frac{3}{16}$ pounds of candy

The unit rate is $\frac{3}{16}$ pounds per person.

Keywords: fraction, unit rate

Learn more about fractions at:

#LearnwithBrainly

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3 years ago

PLEASE HURRY IM BEING TIMED!

ddd [48]

Answer:

The answer is

$\frac{26}{31}$

GOOD LESSONS ♡

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3 years ago

If M is the midpoint of SR, and SR=24, what is the length of SM?

Montano1993 [528]

Do you have a picture you can upload? It’s most likely 24/2 = 12

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3 years ago

What do we do with the coefficients and exponents when we are multiplying polynomials?

Alina [70]

You have to multiply the coefficient and add the exponents of the variables

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3 years ago

A certain CD-ROM disk can store approximately 6.0 × 102 megabytes of information, where 106 bytes = 1 megabyte. If an average wo

klemol [59]

Answer: A. $4.3\times10^7$

Step-by-step explanation:

Given : A certain CD-ROM disk can store approximately $6.0 \times 10^2$ megabytes of information.

1 megabyte = $10^6$ bytes

Then, The storage capacity of CD-ROM disk will be :

$10^6\times 6.0 \times 10^2=6\times10^{6+2}=6\times10^8$

If an average word requires 14 bytes of storage, then the number of words can be stored :-

$\dfrac{6\times10^8}{14}=0.428571428571\times10^8\approx0.43\times10^8=4.3\times10^7$

Hence, number of words can be stored = $4.3\times10^7$

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3 years ago