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djverab [1.8K]
3 years ago
12

X(x+3)(x+3)=0 solve the equation only one answer

Mathematics
1 answer:
timama [110]3 years ago
4 0

Answer:

0

Step-by-step explanation:

it says the answer is zero

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1 gal and 1 quart minus 3 quarts
Mashcka [7]
That would be 128+32=160-96=64?
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0 x + 12 + x = 18<br><br>Solve ?​
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x = 3

Step-by-step explanation:

2x + 12 = 18

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3 years ago
An explosion causes debris to rise vertically with an initial speed of 120 feet per second. The formula h equals negative 16 t s
Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>

Step-by-step explanation:

Given:

Initial speed of debris is, s=120\ ft/s

The height 'h' of the debris above the ground is given as:

h(t)=-16t^2+120t

As per question, h(t)=56\ ft. Therefore,

56=-16t^2+120t

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

-16t^2+120t-56=0\\\textrm{Dividing by -8 throughout, we get}\\\frac{-16}{-8}t^2+\frac{120}{-8}t-\frac{56}{-8}=0\\2t^2-15t+7=0

Using quadratic formula to solve for 't', we get:

t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s

Therefore, the debris will reach a height of 56 ft twice.

When time t=0.5\ s during the upward journey, the debris is at height of 56 ft.

Again after reaching maximum height, the debris falls back and at t=7\ s, the height is 56 ft.

5 0
3 years ago
Help me solve 1 &lt;2n-5 &lt;_7 also please explain
Naddik [55]
I'm not sure if that is supposed to be 7 or -7 If it's -7: 1<2n-5<-7 +5 +5 +5 Add 5 to all parts of the inequality get 2n by itself 6<2n<-2 /2 /2 /2 Divide all parts by 2 to isolate the variable 3
7 0
3 years ago
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